I need help with finding the memory location of d That is the only thing I require assistance with
I need help with finding the memory location of d That is the only thing I require assistance with
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Question
I need help with finding the memory location of d That is the only thing I require assistance with
![else
{
int e = "p/2;
L2:
movq 24(%rbp),%rax
movl (%rax),%eax
movl %eax, %edx
shrl $31, %edx
addl %edx, %eax
sarl
%eax
movl %eax,-12(%rbp)
*p += e-a;
movl 24(%rbp),%rax
movl (%rax), %edx
movl -12(%rbp), %eax
subl 16(%rbp),%eax
addl %eax,%edx
movq 24(%rbp), %rax
movl %edx,(%rax)
}
L4:
addq $16, %rsp
popq %rbp
ret
Give the memory (not register!) location for each of the 5 variables in this function
a =8a5cc38c
p =8a5cc390
с 38а5сс360
d =
e = 8a5cc364](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F72cad98a-02b2-4787-a7eb-1b628d15c30c%2F0665e45d-cdf5-4d36-a1a5-aea728cf9bcd%2Fqbshto8_processed.jpeg&w=3840&q=75)
Transcribed Image Text:else
{
int e = "p/2;
L2:
movq 24(%rbp),%rax
movl (%rax),%eax
movl %eax, %edx
shrl $31, %edx
addl %edx, %eax
sarl
%eax
movl %eax,-12(%rbp)
*p += e-a;
movl 24(%rbp),%rax
movl (%rax), %edx
movl -12(%rbp), %eax
subl 16(%rbp),%eax
addl %eax,%edx
movq 24(%rbp), %rax
movl %edx,(%rax)
}
L4:
addq $16, %rsp
popq %rbp
ret
Give the memory (not register!) location for each of the 5 variables in this function
a =8a5cc38c
p =8a5cc390
с 38а5сс360
d =
e = 8a5cc364
![2. code locations
Consider the following C code and the corresponding assembly code:
void baz(int a, int * p)
{
pushq %rbp
movq %rsp,%rbp
subq $16,%rsp
int c;
C = a-*p;
movl %ecx,16(%rbp)
movq %rdx, 24(%rbp)
movq 24(%rbp), %rax
movl (%rax),%eax
movl 16(%rbp),%edx
subl %eax,%edx
movl %edx,%eax
movl %eax,-4(%rbp)
cmpl $0, -4(%rbp)
je L2
if (c)
{
int d = c*2;
movl -4(%rbp),%eax
addl %eax,%eax
movl %eax,-8(%rbp)
*p -= d;
movl 24(%rbp),%rax
movl (%rax),%eax
subl -8(%rbp),%eax
movl %eax,%edx
movq 24(%rbp), %rax
movl %edx, (%rax)
jmp L4:
(continued on next page)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F72cad98a-02b2-4787-a7eb-1b628d15c30c%2F0665e45d-cdf5-4d36-a1a5-aea728cf9bcd%2Fvd44txc_processed.jpeg&w=3840&q=75)
Transcribed Image Text:2. code locations
Consider the following C code and the corresponding assembly code:
void baz(int a, int * p)
{
pushq %rbp
movq %rsp,%rbp
subq $16,%rsp
int c;
C = a-*p;
movl %ecx,16(%rbp)
movq %rdx, 24(%rbp)
movq 24(%rbp), %rax
movl (%rax),%eax
movl 16(%rbp),%edx
subl %eax,%edx
movl %edx,%eax
movl %eax,-4(%rbp)
cmpl $0, -4(%rbp)
je L2
if (c)
{
int d = c*2;
movl -4(%rbp),%eax
addl %eax,%eax
movl %eax,-8(%rbp)
*p -= d;
movl 24(%rbp),%rax
movl (%rax),%eax
subl -8(%rbp),%eax
movl %eax,%edx
movq 24(%rbp), %rax
movl %edx, (%rax)
jmp L4:
(continued on next page)
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