Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
Related questions
Question
I need help wit number 7
![5.
6.
7.
= 5x+5
-20
2x+20=5x+5
OC bisects <BOD.
m/2 = 3x-7; m/3 = 2x + 5
X=12
OD bisects ZCOE.
m23 = 8 - 5x; m/4=2 - 6x
X = ~6
-20
325-15
e
X
=15
X=5
9.
10. EG = 3p + 8; EH = 100
3x-²7=2x+5
+7
3x=2x+12
Zxzx
X=12
+7
OC bisects LAOE.
m/1 = 5a + 2; m/2 = 2a - 7; m/3 = 4a; m/4 = 7
Assume G is the midpoint of EH. Solve for the variable.
8. EG = 6k + 8; GH = 4k + 28
K=10
<FGD = 18x + 6; <DGH = 10x x -
-0.4
E
Apr](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2b2718fa-2d45-4c6e-acf1-628dfb5e33ec%2Ff54bd51a-a280-4e32-8bb0-8e4202ee6483%2Fifiuyl9_processed.jpeg&w=3840&q=75)
Transcribed Image Text:5.
6.
7.
= 5x+5
-20
2x+20=5x+5
OC bisects <BOD.
m/2 = 3x-7; m/3 = 2x + 5
X=12
OD bisects ZCOE.
m23 = 8 - 5x; m/4=2 - 6x
X = ~6
-20
325-15
e
X
=15
X=5
9.
10. EG = 3p + 8; EH = 100
3x-²7=2x+5
+7
3x=2x+12
Zxzx
X=12
+7
OC bisects LAOE.
m/1 = 5a + 2; m/2 = 2a - 7; m/3 = 4a; m/4 = 7
Assume G is the midpoint of EH. Solve for the variable.
8. EG = 6k + 8; GH = 4k + 28
K=10
<FGD = 18x + 6; <DGH = 10x x -
-0.4
E
Apr
![5.
6.
7.
= 5x+5
-20
2x+20=5x+5
OC bisects <BOD.
m/2 = 3x-7; m/3 = 2x + 5
X=12
OD bisects ZCOE.
m23 = 8 - 5x; m/4=2 - 6x
X = ~6
-20
325-15
e
X
=15
X=5
9.
10. EG = 3p + 8; EH = 100
3x-²7=2x+5
+7
3x=2x+12
Zxzx
X=12
+7
OC bisects LAOE.
m/1 = 5a + 2; m/2 = 2a - 7; m/3 = 4a; m/4 = 7
Assume G is the midpoint of EH. Solve for the variable.
8. EG = 6k + 8; GH = 4k + 28
K=10
<FGD = 18x + 6; <DGH = 10x x -
-0.4
E
Apr](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2b2718fa-2d45-4c6e-acf1-628dfb5e33ec%2Ff54bd51a-a280-4e32-8bb0-8e4202ee6483%2Fkft7dgm_processed.jpeg&w=3840&q=75)
Transcribed Image Text:5.
6.
7.
= 5x+5
-20
2x+20=5x+5
OC bisects <BOD.
m/2 = 3x-7; m/3 = 2x + 5
X=12
OD bisects ZCOE.
m23 = 8 - 5x; m/4=2 - 6x
X = ~6
-20
325-15
e
X
=15
X=5
9.
10. EG = 3p + 8; EH = 100
3x-²7=2x+5
+7
3x=2x+12
Zxzx
X=12
+7
OC bisects LAOE.
m/1 = 5a + 2; m/2 = 2a - 7; m/3 = 4a; m/4 = 7
Assume G is the midpoint of EH. Solve for the variable.
8. EG = 6k + 8; GH = 4k + 28
K=10
<FGD = 18x + 6; <DGH = 10x x -
-0.4
E
Apr
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