I need help using KVL to measure the voltage drops across the following resistors, comparing to my measured values in multisim. The image depicts an electronic circuit diagram with three resistors and a power source, along with three voltmeters (labeled XMM1, XMM2, and XMM3), measuring the voltage across different parts of the circuit.### Circuit Description:- **Power Source (V1):** Supplies 10V to the circuit.- **Resistors:** - **R1:** 500Ω - **R2:** 1500Ω - **R3:** 1kΩ (1000Ω)### Multimeter Readings:- **Multimeter XMM1:** Measures the voltage across R1, showing a reading of 1.667V.- **Multimeter XMM2:** Measures the voltage across R3, displaying a voltage of 3.333V.- **Multimeter XMM3:** Measures the voltage after R2, showing a reading of 5V.### Explanation:- **Total Voltage:** The combined voltage drops (from XMM1 and XMM2) and the remaining voltage measured by XMM3 should add up to the power supply voltage (10V).- **Ohm’s Law Application:** The voltage drop across each resistor is consistent with Ohm’s Law (V = IR), considering the resistances provided and voltage measurements.This setup appears to be a series circuit, where the total voltage is divided among the resistors according to their resistance values.

Answered: I need help using KVL to measure the…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

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I need help using KVL to measure the voltage drops across the following resistors, comparing to my measured values in multisim.

The image depicts an electronic circuit diagram with three resistors and a power source, along with three voltmeters (labeled XMM1, XMM2, and XMM3), measuring the voltage across different parts of the circuit.

### Circuit Description:
- **Power Source (V1):** Supplies 10V to the circuit.
- **Resistors:**
- **R1:** 500Ω
- **R2:** 1500Ω
- **R3:** 1kΩ (1000Ω)

### Multimeter Readings:
- **Multimeter XMM1:** Measures the voltage across R1, showing a reading of 1.667V.
- **Multimeter XMM2:** Measures the voltage across R3, displaying a voltage of 3.333V.
- **Multimeter XMM3:** Measures the voltage after R2, showing a reading of 5V.

### Explanation:
- **Total Voltage:** The combined voltage drops (from XMM1 and XMM2) and the remaining voltage measured by XMM3 should add up to the power supply voltage (10V).
- **Ohm’s Law Application:** The voltage drop across each resistor is consistent with Ohm’s Law (V = IR), considering the resistances provided and voltage measurements.

This setup appears to be a series circuit, where the total voltage is divided among the resistors according to their resistance values.

Expert Solution

Step 1

Draw the circuit first:

Apply the KVL and find the value of I:

$10 - R_{1} I - R_{3} I - R_{4} I = 0 10 - 500 I - 1000 I - 1500 I = 0 3000 I = 10 I = \frac{10}{3000} I = 3.33 m A$

Step 2 Now find the value across each resistor

First find voltage V₁ across R₁ resistor:

$T h e v o l t a g e V_{1} i s g i v e n b y : V_{1} = I R_{1} V_{1} = 3.33 \times 10^{- 3} \times 500 V_{1} = 1.667 V$

Now find voltage V₂across R₂ resistor:

$T h e v o l t a g e V_{2} i s g i v e n b y : V_{2} = I R_{2} V_{2} = 3.33 \times 10^{- 3} \times 1500 V_{2} = 4.99 V V_{2} = 5 V$

Now find voltage V₃across R₃ resistor:

$T h e v o l t a g e V_{3} i s g i v e n b y : V_{3} = I R_{3} V_{3} = 3.33 \times 10^{- 3} \times 1000 V_{3} = 3.33 V V_{3} = 3.33 V$

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