I need help understanding the calculations written in blue and how they got 0.8 and 0.4 for fiber b and how they calculated the answer in blue i need a step by step calculation of how they got 0.232
I need help understanding the calculations written in blue and how they got 0.8 and 0.4 for fiber b and how they calculated the answer in blue i need a step by step calculation of how they got 0.232
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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I need help understanding the calculations written in blue
and how they got 0.8 and 0.4 for fiber b and how they calculated
the answer in blue i need a step by step calculation of how they got 0.232
![(b)
mine the travel time from finger to brain along each of the three fibers.
Suppose the nerve fibers connect a finger to your brain, a distance of 1.2 m. Deter-
Fiber A: d = vt → t= d/v= (1.2 m)/(2 m/s) = 0.6s
Fiber C: d = vt → t= d/v= (1.2 m)/(25 m/s) =[0.048 s
Fiber B is the tricky one. Two-thirds of the total distance (0.8 m) is covered at 25 m/s, and
one-third of the total distance (0.4 m) is covered at 2 m/s.
0.8 m =
= (25 m/s) t1 → t1 = 0.032 s
0.4 m = (2 m/s) t2 → t2 = 0.2s
ti + t2 = 0.232 s](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4d62cc64-0378-4638-9893-20a25cf6ef2f%2Fca319646-8b8a-4be1-bdff-412f841695f0%2Fn2eyzm_processed.png&w=3840&q=75)
Transcribed Image Text:(b)
mine the travel time from finger to brain along each of the three fibers.
Suppose the nerve fibers connect a finger to your brain, a distance of 1.2 m. Deter-
Fiber A: d = vt → t= d/v= (1.2 m)/(2 m/s) = 0.6s
Fiber C: d = vt → t= d/v= (1.2 m)/(25 m/s) =[0.048 s
Fiber B is the tricky one. Two-thirds of the total distance (0.8 m) is covered at 25 m/s, and
one-third of the total distance (0.4 m) is covered at 2 m/s.
0.8 m =
= (25 m/s) t1 → t1 = 0.032 s
0.4 m = (2 m/s) t2 → t2 = 0.2s
ti + t2 = 0.232 s
![7. Nerve impulses are electrical signals that propagate along
nerve fibers consisting of many axons connected end-to-
end. Axons come in two varieties: insulated (covered with
a myelin sheath) and uninsulated. Myelinated axons con-
duct nerve impulses at a speed of about 25 m/s, which is
much faster than unmyelinated axons (about 2.0 m/s). The
figure shows small portions of three nerve fibers consisting
of axons of equal size. Two-thirds of the axons in fiber B
are myelinated.
Unmyelinated fiber A
Partially myelinated fiber B
individual
ахоns
Fully myelinated fiber C](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4d62cc64-0378-4638-9893-20a25cf6ef2f%2Fca319646-8b8a-4be1-bdff-412f841695f0%2Fq8dsjo_processed.png&w=3840&q=75)
Transcribed Image Text:7. Nerve impulses are electrical signals that propagate along
nerve fibers consisting of many axons connected end-to-
end. Axons come in two varieties: insulated (covered with
a myelin sheath) and uninsulated. Myelinated axons con-
duct nerve impulses at a speed of about 25 m/s, which is
much faster than unmyelinated axons (about 2.0 m/s). The
figure shows small portions of three nerve fibers consisting
of axons of equal size. Two-thirds of the axons in fiber B
are myelinated.
Unmyelinated fiber A
Partially myelinated fiber B
individual
ахоns
Fully myelinated fiber C
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