I need help to solve this Explain the concept of wave propagation in a good conducting medium and hence derive the following parameters: i. Attenuation and phase constant ii. Skin depth iii. Wave velocity and iv. Wave Impedance
I need help to solve this Explain the concept of wave propagation in a good conducting medium and hence derive the following parameters: i. Attenuation and phase constant ii. Skin depth iii. Wave velocity and iv. Wave Impedance
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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I need help to solve this
Explain the concept of wave propagation in a good conducting medium and hence derive the following parameters:
i. Attenuation and phase constant
ii. Skin depth
iii. Wave velocity and iv. Wave Impedance
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Follow-up Question
![We know that
ß = W
14
ME
2
For good conductor, I >> 1 => />
عل
ß=
2
14
{1+ (1/2) = + 1}]}
WE
how we get this equution?
But it I also
WE
o
WE.
also ~ WE
= W| ME
2
X
Ō
WE
عله
шмо
2
7 B = 21Tf Mo
2
3 =
TTF MO rad/m](https://content.bartleby.com/qna-images/question/63deb46e-49e3-4f5e-a27e-0def6e724536/06ef7b00-de8b-4673-9a52-862b450c1c82/fif82nl_thumbnail.jpeg)
Transcribed Image Text:We know that
ß = W
14
ME
2
For good conductor, I >> 1 => />
عل
ß=
2
14
{1+ (1/2) = + 1}]}
WE
how we get this equution?
But it I also
WE
o
WE.
also ~ WE
= W| ME
2
X
Ō
WE
عله
шмо
2
7 B = 21Tf Mo
2
3 =
TTF MO rad/m
Solution
Follow-up Question
From where get this formula ?!

Transcribed Image Text:Solution b BY BARTLEBY EXPERT
Step 1
We know that
x =
3
=>
МЕ
x = W
11+/012
(WE
For good conductor, WE
o >>I
МЕ
11/²2 { ₁ + √ √ 2 - 1 }
WE
=> x = w M8 x WE
-1}
from
where
derive
this
equation ??
2
.. (1 + (5 (1) ²
ωε
≈1+5
WE
Solution
Follow-up Question
I need mathmatics solving for derive Attenuation, phase constant
Skin depth,Wave velocity and Wave Impedance .
like this picture I proveded but in clearly explaintion to understand the concept

Transcribed Image Text:W
WE
Attenuation
WE
α =
x =
ß =
(6) >>
B = w
∞ -
ß
w=2πif
>>
w
>>1
w / Ne
1
Ce
لا
√₁
№² 2 √1-4(62²22)-13
Jc >> Jd
NE
2
V
Jose
どでの
2
√TTfNG
13
Neps Im
Nep /n
√HE WHE
LE
हर
fro
WON = √√TifNG
2
2
NE 1/1/12 +13
2
+
Nepes /m
13
rad/m
Solution
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