I need help on the percent difference !! 4. Data and calculations for 50-mL graduated cylinder:12.67(6g106.43772.67032.7e7Mass of empty 50-mL cylinderVolume read for 50-mL cylinder32.5mL105.431gMass of cylinder + waterMass of water in cylinder37.767gby differenceCalculated volume of waterShow your calculation of the volume:Percent difference for 50-mL cylinderShow your calculation of the percent difference:

In the given question we have to calculate volume of water and Percent difference for 50 mL…

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Science

Chemistry

I need help on the percent difference !!

Chemistry: Principles and Practice

3rd Edition

ISBN:9780534420123

Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Chapter1: Introduction To Chemistry

Section: Chapter Questions

Problem 1.68QE

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I asked this question earlier but I think I forgot to include a conversion wht we know : mm of citrix acid = 192.14g/moldensity of citrix acid =166g/cm3 1 lime = 2tbsp of juice = 6 tsp 1tsp = 4.929x10-3L Q: assume citrix acid makes up 7.96% by volume of the lime juice . How many moles of citrix acid are in the recipe ( calls for 1 lime juice)
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Hi. I am trying to calculate the percent of water in an uknown hydrate. The given data is: mass of empty crucible +lid = 27.19g mass of crucible + lid and hydrate = 28.58g mass of crucible + lid and sample after heating(anhydrous salt) = 27.68g % water in hydrate formula = mass of water/mass of hydrate * 100
How can I round this number? Example: Cp = qmetal = -365.4 cal = 0.0501 cal/g°C m∆T (109.7g)(-66.5°C) help me with this Cp = qmetal = -77.0 cal = 0.09803921cal/g°C m∆T (109.7g)(-66.5°C)
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