I need help finding the g average and standard deviation. Then answering number 1 - is the accepted value within one SD from your average value? And how do I find the percent error?

MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
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I need help finding the g average and standard deviation. Then answering number 1 - is the accepted value within one SD from your average value? And how do I find the percent error? 

O mass A m 1.000 kg
k Plots v
O mass A
O Sync
2.29E-3
V Auto
mass A (t, y)
2.29E-3
V Auto-
-0.2
E-0.4
-0.6
0.05
0.10
0.15
0.20
0.25
0.30
0.35
t (s)
t=0.000 s y-2.293E-3 m
mass A (t, Vy)
-1.5
-2.0
3-2.5
-3.0
V Auto
0.3(3.67E-1
0.05
0.10
0.15
0.20
0.25
t(s)
t=0.000 s vy= m/s
0750 m
I Columns
O mass A
t(s)
X (m)
у (m)
0.000
2.293E-3
2.293E-3
0.033
2.776E-17
-4.128E-2
0.067
-4.587E-3
-7.339E-2
0.100
0.133
0.167
0.200|
-2.293E-3
-0.122
-6.880E-3
-0.177
2.776E-17
-0.239
4.587E-3
-0.303
0.303
-0.376
-0.456
-0.553
-0.667
-0.773
0.233
2.776E-17
0.267
-6.880E-3
mass A selected (set mass on toolbar, shift-click to re-mark highlighted position)
0.300
2.776E-17
015 100%
I
0.333
2.776E-17
0.367
-2.293E-3
IMG592656387315040114.mp4
(sju) A
Transcribed Image Text:O mass A m 1.000 kg k Plots v O mass A O Sync 2.29E-3 V Auto mass A (t, y) 2.29E-3 V Auto- -0.2 E-0.4 -0.6 0.05 0.10 0.15 0.20 0.25 0.30 0.35 t (s) t=0.000 s y-2.293E-3 m mass A (t, Vy) -1.5 -2.0 3-2.5 -3.0 V Auto 0.3(3.67E-1 0.05 0.10 0.15 0.20 0.25 t(s) t=0.000 s vy= m/s 0750 m I Columns O mass A t(s) X (m) у (m) 0.000 2.293E-3 2.293E-3 0.033 2.776E-17 -4.128E-2 0.067 -4.587E-3 -7.339E-2 0.100 0.133 0.167 0.200| -2.293E-3 -0.122 -6.880E-3 -0.177 2.776E-17 -0.239 4.587E-3 -0.303 0.303 -0.376 -0.456 -0.553 -0.667 -0.773 0.233 2.776E-17 0.267 -6.880E-3 mass A selected (set mass on toolbar, shift-click to re-mark highlighted position) 0.300 2.776E-17 015 100% I 0.333 2.776E-17 0.367 -2.293E-3 IMG592656387315040114.mp4 (sju) A
CURVE FIT DATA -
Partner Name
Trial
gexp = |2A|
14.07
14.098
la
-7.035EO
eoט. ר
1b
1c
2a
-7.643EO
-6.043ED
2b
2c
За
-9.20160
ר.1. ר-
3b
3c
g average
og
Transcribed Image Text:CURVE FIT DATA - Partner Name Trial gexp = |2A| 14.07 14.098 la -7.035EO eoט. ר 1b 1c 2a -7.643EO -6.043ED 2b 2c За -9.20160 ר.1. ר- 3b 3c g average og
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