I know that using a corollary that the congruence x2 ≡ 0 (mod p) that the only solutions are + and - 1 but thats when p is prime. How would i go about proving this... Prove that if n ≡ 2(mod 4), then n can't be written as am for any integer m with m > 1.
I know that using a corollary that the congruence x2 ≡ 0 (mod p) that the only solutions are + and - 1 but thats when p is prime. How would i go about proving this... Prove that if n ≡ 2(mod 4), then n can't be written as am for any integer m with m > 1.
Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter5: Factoring Polynomials
Section5.4: Multiplying Binomials Mentally
Problem 49WE
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I know that using a corollary that the congruence x2 ≡ 0 (mod p) that the only solutions are + and - 1 but thats when p is prime. How would i go about proving this...
Prove that if n ≡ 2(mod 4), then n can't be written as am for any integer m with m > 1.
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