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i just recently asked an expert about this assigment and so far it has given me 6.67% of of 10  here is the instructions again: Assume that a gallon of paint covers about 350 square feet of wall space. Create an application with a main() method that prompts the user for the length, width, and height of a rectangular room. Pass these three values to a method that does the following: Calculates the wall area for a room Passes the calculated wall area to another method that calculates and returns the number of gallons of paint needed Displays the number of gallons needed Computes the price based on a paint price of $32 per gallon, assuming that the painter can buy any fraction of a gallon of paint at the same price as a whole gallon Returns the price to the main() method The main() method displays the final price. For example: You will need 2.0 gallons The price to paint the room is $64.0  here is my code:  import java.util.Scanner; public class PaintCalculator {      static int AreaPerGalllon = 350;      static double PricePerGallon = 32;     public static void main (String args[]) {         int length;         int height;         int width;         Scanner in = new Scanner(System.in);         System.out.println("Enter length");         length = in.nextInt();         System.out.println("Enter width");         width = in.nextInt();         System.out.println("Enter Height");         height = in.nextInt();         double price=computeArea(length, width, height);         System.out.println("The price to paint the room is $"+price);     }     public static double computeArea(double length, double width, double height) {         double area = length * height * 2 + width * height * 2;          double requiredGallons=computeGallons(area);       System.out.println("You will need "+requiredGallons+ " gallons");       double price=requiredGallons*PricePerGallon;       return price;     }     public static double computeGallons(double area) {          return area/AreaPerGalllon;    } }

i just recently asked an expert about this assigment and so far it has given me 6.67% of of 10  here is the instructions again: Assume that a gallon of paint covers about 350 square feet of wall space. Create an application with a main() method that prompts the user for the length, width, and height of a rectangular room. Pass these three values to a method that does the following: Calculates the wall area for a room Passes the calculated wall area to another method that calculates and returns the number of gallons of paint needed Displays the number of gallons needed Computes the price based on a paint price of $32 per gallon, assuming that the painter can buy any fraction of a gallon of paint at the same price as a whole gallon Returns the price to the main() method The main() method displays the final price. For example: You will need 2.0 gallons The price to paint the room is $64.0  here is my code:  import java.util.Scanner; public class PaintCalculator {      static int AreaPerGalllon = 350;      static double PricePerGallon = 32;     public static void main (String args[]) {         int length;         int height;         int width;         Scanner in = new Scanner(System.in);         System.out.println("Enter length");         length = in.nextInt();         System.out.println("Enter width");         width = in.nextInt();         System.out.println("Enter Height");         height = in.nextInt();         double price=computeArea(length, width, height);         System.out.println("The price to paint the room is $"+price);     }     public static double computeArea(double length, double width, double height) {         double area = length * height * 2 + width * height * 2;          double requiredGallons=computeGallons(area);       System.out.println("You will need "+requiredGallons+ " gallons");       double price=requiredGallons*PricePerGallon;       return price;     }     public static double computeGallons(double area) {          return area/AreaPerGalllon;    } }

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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i just recently asked an expert about this assigment and so far it has given me 6.67% of of 10 

here is the instructions again:

Assume that a gallon of paint covers about 350 square feet of wall space. Create an application with a main() method that prompts the user for the length, width, and height of a rectangular room. Pass these three values to a method that does the following:

  • Calculates the wall area for a room
  • Passes the calculated wall area to another method that calculates and returns the number of gallons of paint needed
  • Displays the number of gallons needed
  • Computes the price based on a paint price of $32 per gallon, assuming that the painter can buy any fraction of a gallon of paint at the same price as a whole gallon
  • Returns the price to the main() method

The main() method displays the final price. For example:

You will need 2.0 gallons The price to paint the room is $64.0

 here is my code: 

import java.util.Scanner;
public class PaintCalculator {
     static int AreaPerGalllon = 350;
     static double PricePerGallon = 32;
    public static void main (String args[]) {
        int length;
        int height;
        int width;
        Scanner in = new Scanner(System.in);
        System.out.println("Enter length");
        length = in.nextInt();
        System.out.println("Enter width");
        width = in.nextInt();
        System.out.println("Enter Height");
        height = in.nextInt();
        double price=computeArea(length, width, height);
        System.out.println("The price to paint the room is $"+price);

    }

    public static double computeArea(double length, double width, double height) {
        double area = length * height * 2 + width * height * 2;   
      double requiredGallons=computeGallons(area);
      System.out.println("You will need "+requiredGallons+ " gallons");
      double price=requiredGallons*PricePerGallon;
      return price;
    }
    public static double computeGallons(double area) {
         return area/AreaPerGalllon;
   }
}
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