I) Immiscible Liquid-Liquid Extraction: A feed of 13,500 kg/hr consists of 8.0 wt% acetic acid in water. The removal of acetic acid is to be accomplished by liquid-liquid extraction in water at 25°C. The raffinate is to contain no more than 1.0 wt % acetic acid. SOLVENT K The following four solvents (and accompanying distribution coefficients are being considered. Water and each solvent can be considered immiscible. Methyl acetate Isopropyl ether Heptadecanol Chloroform 1.273 0.429 0.312 0.178 For each solvent, estimate the flow rate (kg/hr) if a single equilibrium stage is used to achieve the desired separation. Discuss the solvent choices and indicate which may be the best option.

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
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Chapter1: Introduction
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Separation Process Question

Reading/References: Ch 8 [Seader, Henley, & Roper (SHR) Textbook]
1) Immiscible Liquid-Liquid Extraction: A feed of 13,500 kg/hr consists of 8.0 wt% acetic acid in water. The
removal of acetic acid is to be accomplished by liquid-liquid extraction in water at 25°C. The raffinate is to
contain no more than 1.0 wt % acetic acid.
SOLVENT
K
The following four solvents (and accompanying distribution
coefficients are being considered. Water and each solvent can be
considered immiscible.
1.273
Methyl acetate
Isopropyl ether
Heptadecanol
Chloroform
0.429
0.312
For each solvent, estimate the flow rate (kg/hr) if a single
equilibrium stage is used to achieve the desired separation.
0.178
Discuss the solvent choices and indicate which may be the best option.
Transcribed Image Text:Reading/References: Ch 8 [Seader, Henley, & Roper (SHR) Textbook] 1) Immiscible Liquid-Liquid Extraction: A feed of 13,500 kg/hr consists of 8.0 wt% acetic acid in water. The removal of acetic acid is to be accomplished by liquid-liquid extraction in water at 25°C. The raffinate is to contain no more than 1.0 wt % acetic acid. SOLVENT K The following four solvents (and accompanying distribution coefficients are being considered. Water and each solvent can be considered immiscible. 1.273 Methyl acetate Isopropyl ether Heptadecanol Chloroform 0.429 0.312 For each solvent, estimate the flow rate (kg/hr) if a single equilibrium stage is used to achieve the desired separation. 0.178 Discuss the solvent choices and indicate which may be the best option.
100
Water
90
80
Glycol
100
Raffinate
20
80
30
40
Furfural
Glycol
Extract
80
0.
0-
Water
0-
100-4 Furfural
09
10 B
Furfural
Water
10,
06
Tie lines
20
30
09
40
E.
Plait point
09
40
30
06
glycol
Ethylene
Transcribed Image Text:100 Water 90 80 Glycol 100 Raffinate 20 80 30 40 Furfural Glycol Extract 80 0. 0- Water 0- 100-4 Furfural 09 10 B Furfural Water 10, 06 Tie lines 20 30 09 40 E. Plait point 09 40 30 06 glycol Ethylene
Expert Solution
Step 1

Given,

Feed, F = 13500 kg/hr

wt% of acetic acid in water is 8%

 

Calculate the flow of acetic acid and water as follows:

flow of acetic acid = F×8%= 13500 kg/hr×0.08= 1080 kg/hr

 

flow of water = F×92%= 13500 kg/hr×0.92= 12420 kg/hr

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