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I How much work is done (by a battery, generator or Sume other source of Potential difference) in war Moving Avogadro's number of elections from an Initial Point where the electric Potential is 7:30 v to a Point where the electric Potential is - 5.801? (answer in My)

I How much work is done (by a battery, generator or Sume other source of Potential difference) in war Moving Avogadro's number of elections from an Initial Point where the electric Potential is 7:30 v to a Point where the electric Potential is - 5.801? (answer in My)

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
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### Understanding Work Done in Moving Electrons #### Problem Statement: **How much work is done (by a battery, generator, or some other source of potential difference) in moving Avogadro's number of electrons from an initial point where the electric potential is 7.30 V to a point where the electric potential is -5.80 V? (answer in MJ)** #### Explanation: This problem involves calculating the work done when moving a large number of electrons between two points with different electric potentials. By understanding the concept of electric potential difference and the quantity of charge represented by Avogadro's number of electrons, you can determine the work done in this process. **Given:** - Initial electric potential (V_initial) = 7.30 V - Final electric potential (V_final) = -5.80 V - Number of electrons = Avogadro's number (approximately \(6.022 \times 10^{23}\) electrons) #### Steps: 1. **Calculate the potential difference (ΔV):** \[ ΔV = V_{final} - V_{initial} = -5.80 \, V - 7.30 \, V = -13.10 \, V \] 2. **Determine the charge of one electron:** The charge of one electron (e) is approximately \(-1.602 \times 10^{-19}\) Coulombs. 3. **Total charge (Q) of Avogadro's number of electrons:** \[ Q = (6.022 \times 10^{23}) \times (-1.602 \times 10^{-19}) \, C = -9.648 \times 10^{4} \, C \] 4. **Calculate the work done (W):** Work done \(W\) is given by the product of the total charge and the potential difference: \[ W = Q \times ΔV = (-9.648 \times 10^4 \, C) \times (-13.10 \, V) = 1.264 \times 10^6 \, J \] 5. **Convert work from joules to megajoules (MJ):** \[ 1 \, MJ = 10^6 \, J \] Therefore, \[ W = 1.264 \
Transcribed Image Text:### Understanding Work Done in Moving Electrons #### Problem Statement: **How much work is done (by a battery, generator, or some other source of potential difference) in moving Avogadro's number of electrons from an initial point where the electric potential is 7.30 V to a point where the electric potential is -5.80 V? (answer in MJ)** #### Explanation: This problem involves calculating the work done when moving a large number of electrons between two points with different electric potentials. By understanding the concept of electric potential difference and the quantity of charge represented by Avogadro's number of electrons, you can determine the work done in this process. **Given:** - Initial electric potential (V_initial) = 7.30 V - Final electric potential (V_final) = -5.80 V - Number of electrons = Avogadro's number (approximately \(6.022 \times 10^{23}\) electrons) #### Steps: 1. **Calculate the potential difference (ΔV):** \[ ΔV = V_{final} - V_{initial} = -5.80 \, V - 7.30 \, V = -13.10 \, V \] 2. **Determine the charge of one electron:** The charge of one electron (e) is approximately \(-1.602 \times 10^{-19}\) Coulombs. 3. **Total charge (Q) of Avogadro's number of electrons:** \[ Q = (6.022 \times 10^{23}) \times (-1.602 \times 10^{-19}) \, C = -9.648 \times 10^{4} \, C \] 4. **Calculate the work done (W):** Work done \(W\) is given by the product of the total charge and the potential difference: \[ W = Q \times ΔV = (-9.648 \times 10^4 \, C) \times (-13.10 \, V) = 1.264 \times 10^6 \, J \] 5. **Convert work from joules to megajoules (MJ):** \[ 1 \, MJ = 10^6 \, J \] Therefore, \[ W = 1.264 \
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