I have this IP address 10.203.39.231 and I need to pick only the 4th octet from it. I did use ipAddress.substring(8, ipAddress.lastIndexOf("."). I need a .split method to help me out with this
I have this IP address 10.203.39.231 and I need to pick only the 4th octet from it. I did use ipAddress.substring(8, ipAddress.lastIndexOf("."). I need a .split method to help me out with this
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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I have this IP address 10.203.39.231 and I need to pick only the 4th octet from it. I did use ipAddress.substring(8, ipAddress.lastIndexOf("."). I need a .split method to help me out with this
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This is what I did since mine is in Java:
private String generateId(String ipAddress){
if(ipAddress != null){
String [] to4thOctet = ipAddress.split(".");
String toParse = to4thOctet[3];
return BuildConfig.USER_ID + toParse;
} else{
return username;
}
}
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