Answered: I have this IP address 10.203.39.231…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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I have this IP address 10.203.39.231 and I need to pick only the 4th octet from it. I did use ipAddress.substring(8, ipAddress.lastIndexOf("."). I need a .split method to help me out with this

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This is what I did since mine is in Java:
private String generateId(String ipAddress){

if(ipAddress != null){

String [] to4thOctet = ipAddress.split(".");

String toParse = to4thOctet[3];

return BuildConfig.USER_ID + toParse;

} else{

return username;

}

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