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- I have purchased a machine worth P1,564,748.00. And it needs maintenance at the end of every 6 months starting 5 years after its purchased date and maintenance will be needed for the next 10 years of its useful life. The maintenance cost is equivalent to the 2% of the total machine cost. How much money should be prepare today to finance the requirement if the interest rate is 0.10 compounded quarterly? Help me pls. Ill upvote :)I have purchased a machine worth P1.862,585.00. And it needs maintenance at the end of every 6 months starting 5 years after its purchased date and maintenance will be needed for the next 10 years of its useful life. The maintenance cost is equivalent to the 2% of the total machine cost. How much money should be prepare today to finance the requirement if the interest rate is 0.10 compounded quarterly?Electro Corporation bought a new machine and agreed to pay for it in equal annual installments of 5,000 at the end of each of the next 5 years. Assume a prevailing interest rate of 15%. The present value of an ordinary annuity of 1 at 15% for 5 periods is 3.35. The future amount of an ordinary annuity of 1 at 15% for 5 periods is 6.74. The present value of 1 at 15% for 5 periods is 0.5. How much should Electro record as the cost of the machine? a. 12,500 b. 16,750 c. 25,000 d. 33,700
- A machine is purchased for P100,000. If the annual maintenance cost is P1,800, determine the capitalized cost of perpetual service with an interest rate of 8%. P325,000 P425,000 P525,000 P625,000The net present value of the cost of operating a machine for the next five years is R8 947. The discount rate used by the company for investment appraisal is 9% Required What is the equivalent annual cost, and the present value of the cost in perpetuity of operating this machine? (Use discount factors to three decimal places) a. Equivalent annual cost: R92 825.56; cost in perpetuity: R9 283 b. Equivalent annual cost: R2 300; cost in perpetuity: R25 555.56 c. Equivalent annual cost: R2 000; cost in perpetuity: R20 000.00 d. Equivalent annual cost: R9 283; cost in perpetuity: R92 825.56The following present value factors are provided for use in this problem. Periods Present Valueof $1 at 11% Present Value of anAnnuity of $1 at 11% 1 0.9009 0.9009 2 0.8116 1.7125 3 0.7312 2.4437 4 0.6587 3.1024 Cliff Co. wants to purchase a machine for $62,000, but needs to earn a return of 11%. The expected year-end net cash flows are $24,000 in each of the first three years, and $28,000 in the fourth year. What is the machine's net present value? Multiple Choice $(3,351). $15,093. $77,093. $(43,556). $100,000.
- Question 2. I have purchased a machine worth ₱1,893,877.00. And it needs maintenance every 6 months starting from its purchased date for the first 10 years of its useful life. The maintenance cost is equivalent to the 2% of the total machine cost. How much money should be prepare today to finance the requirement if the interest rate is 0.10 compounded quarterly?What is the capitalized cost of a structure that will require construction costof P1,000,000 immediately and P800,00 each year for the next 4 yearsand annual year –end maintenance of P36,000 plus the expenditure ofP200,000 an the end of each 10-year period for replacement? Assume12% interest rate.The following present value factors are provided for use in this problem. Present Value Present Value of an Periods of $1 at 6% Annuity of $1 at 6% 1 0.9434 0.9434 0.8900 1.8334 3. 0.8396 2.6730 4. 0.7921 3.4651 Finch Co. wants to purchase a machine for $40,200, but needs to earn a 6% return. The expected year-end net cash flows are $17,000 in each of the first three years, and $12,000 in the fourth year. What is the machine's net present value (round the final answer to the nearest whole dollar)?
- Capitalized cost is an application of perpetuity. It is the sum of the first cost and the present worth of all future payments and replacements. A machine costs P300,000 new, and must be replaced at the end of each 15 years. If the annual maintenance required is P5,000, find the capitalized cost, if money is worth 5% and the salvage value is P50,000. First Cost 300000 Present worth of the annual maintenance cost *Letters only Perpetuity of the depreciation cost Capitalized cost a. 178,700 b. 231,700 c. 321,500 d. 400,500 e. 127,700 a. 372,700 b. 441,700 c. 529,500 d. 609,500 e. 631,700An asphalt road requires no upkeep until the end of 2 years when P60,000 will beneeded for repairs. After this P90,000 will be needed for repairs at the end of each yearfor the next 3 years, then P120,000 at the end of each year for the next 4 years. Ifmoney is worth 14% compounded annually, what was the equivalent uniform annualcost for the 9-year period?Solve it using formula not with excelA special-purpose machine toolset would cost $30.000. 1l1e entire capitalexpenditure ($30.000) is 10 be borrowed with the stipulation that it be repaid by two equal end-of-year payments at 12% compounded annually. 11rn tool is expected to provide annual savings (in the material) of $45,000 for two years and is to be depreciated by the MACRS Three-year recovery period.111is special machine tool will require annual O&M costs in the amount of $12,000.111e salvage value at the end of two years is expected 10 be $9,000. Assuming a marginal tax rate of 40% and MARR of 15%. what is the net present worth of this project?