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Need help with PDF and CDF questions. Please see attached image.

Need help with PDF and CDF questions. Please see attached image.

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter3: Functions And Graphs
Section3.2: Graphs Of Equations
Problem 24E
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f(x) = +/1 +11 t 1-X , 0<x< 1 J X > I a) Find the probability P(X>1) b) Find the probability P(x> ) () Find the probability PC = < x < 2 | X > ) d) Find the CDF F(x)
Transcribed Image Text:f(x) = +/1 +11 t 1-X , 0<x< 1 J X > I a) Find the probability P(X>1) b) Find the probability P(x> ) () Find the probability PC = < x < 2 | X > ) d) Find the CDF F(x)
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Follow-up Question

I have a question to the solution provided for my follow up question part d

Please refer to my attached image. Why can't I approach "If t > 1" this way? 

t S If t > 1, F(t) = √ f(x) dx CDF : F(t) = O +4 11 > O S S f(x) dx + S f(x) dx + Š f(x) dx -1 1 t -X 5 = 똥 S = 0 + √²/²x³²x + 5 ½ e ²² dx -4e [x = ($) (+) [× ² / + ( + ² ) [e * † = - डे 5 In ut at = 5-4e 5 t <0 5-46(1-t) 5 XPX 4 4elet-e¹) 5 (4 e'-t - 4) 5 (1-t) ostsi t>1
Transcribed Image Text:t S If t > 1, F(t) = √ f(x) dx CDF : F(t) = O +4 11 > O S S f(x) dx + S f(x) dx + Š f(x) dx -1 1 t -X 5 = 똥 S = 0 + √²/²x³²x + 5 ½ e ²² dx -4e [x = ($) (+) [× ² / + ( + ² ) [e * † = - डे 5 In ut at = 5-4e 5 t <0 5-46(1-t) 5 XPX 4 4elet-e¹) 5 (4 e'-t - 4) 5 (1-t) ostsi t>1
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Follow-up Question

The solution is missing part d

please see my attempt for part d in attached image. I still don't know how to proceed with "If t > 1"

10. d) Find CDF F(x) If t < 0, F(t) = P(x<t) = If t > 1 If os t<! 쏨 F(t) = St f(x) dx = S 4² x ²³ x D 7 P S₁0dx = 0 11 =(赤)()[x 七 t = // (+²-0²) = 4/20
Transcribed Image Text:10. d) Find CDF F(x) If t < 0, F(t) = P(x<t) = If t > 1 If os t<! 쏨 F(t) = St f(x) dx = S 4² x ²³ x D 7 P S₁0dx = 0 11 =(赤)()[x 七 t = // (+²-0²) = 4/20
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