(i) Flux of oxygen gas in kgmol/s•m² and gmol/s·cm². (ii) Flux of propane gas in kgmol/s•m². (iii) Partial pressure of oxygen gas at a point 5 cm from either end.

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Oxygen and propane gas are contained in a tube 5 mm in diameter and 10 cm
long at 298.15K and a uniform constant pressure of 1.0 atm. The partial pressure
of O2 at one end of the tube is 0.06 atm and at the other end is 0.02 atm. The
diffusivity is 0.0890×10ª m²/s. Calculate the following for equimolar
counterdiffusion.
(i)
Flux of oxygen gas in kgmol/s•m² and gmol/s·cm².
(ii)
Flux of propane gas in kgmol/s•m².
(iii)
Partial pressure of oxygen gas at a point 5 cm from either end.
Plot the total pressure P, partial pressures pa and på against the diffusion
distance z.
(iv)
Transcribed Image Text:Oxygen and propane gas are contained in a tube 5 mm in diameter and 10 cm long at 298.15K and a uniform constant pressure of 1.0 atm. The partial pressure of O2 at one end of the tube is 0.06 atm and at the other end is 0.02 atm. The diffusivity is 0.0890×10ª m²/s. Calculate the following for equimolar counterdiffusion. (i) Flux of oxygen gas in kgmol/s•m² and gmol/s·cm². (ii) Flux of propane gas in kgmol/s•m². (iii) Partial pressure of oxygen gas at a point 5 cm from either end. Plot the total pressure P, partial pressures pa and på against the diffusion distance z. (iv)
Expert Solution
Step 1

Given that

d = 5 mm = 0.005m

Z =10 cm = 0.1 m

Temp,T =298.15 k

Total pressure ,P =1 atm

PA1 = 0.06 atm

PA2 = 0.02 atm 

Diffusivity ,DAB = 0.089 x 10-4 m2/s

 

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