I dont understand how to distrubute to get the 10.3

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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I dont understand how to distrubute to get the 10.3

#### Numerical Solution Using Euler's Method

To solve the differential equation numerically, we use Euler's Method. The general form of Euler's method is:

\[ y_{n+1} = y_n + h f(x_n, y_n) \]

The given differential equation is:

\[ y' = 2x - 3y + 1 \]

with the initial condition:

\[ y(1) = 6 \]

We are given a step size \( h = 0.1 \).

**Step-by-Step Solution:**

1. **Initial Values:**
   - \( x_0 = 1 \)
   - \( y_0 = 6 \)

2. **Step 1:**
   - Calculate \( y_1 \):
   \[ y_1 = y_0 + h f(x_0, y_0) \]
   Given \( f(x, y) = 2x - 3y + 1 \):
   \[ y_1 = 6 + 0.1 \cdot f(1, 6) \]
   \[ y_1 = 6 + 0.1 \cdot (-15) \]
   \[ y_1 = 4.5 \]
   Hence, \( y(1.1) = 4.5 \).

3. **Step 2:**
   - Calculate \( y_2 \):
   \[ y_2 = y_1 + h f(x_1, y_1) \]
   Using \( x_1 = 1.1 \) and \( y_1 = 4.5 \):
   \[ y_2 = 4.5 + 0.1 \cdot f(1.1, 4.5) \]
   \[ y_2 = 4.5 + 0.1 \cdot (-10.3) \]
   \[ y_2 = 3.47 \]
   Hence, \( y(1.2) = 3.47 \).

Thus, using Euler's Method, the value of \( y \) at \( x = 1.2 \) is \( 3.47 \).
Transcribed Image Text:#### Numerical Solution Using Euler's Method To solve the differential equation numerically, we use Euler's Method. The general form of Euler's method is: \[ y_{n+1} = y_n + h f(x_n, y_n) \] The given differential equation is: \[ y' = 2x - 3y + 1 \] with the initial condition: \[ y(1) = 6 \] We are given a step size \( h = 0.1 \). **Step-by-Step Solution:** 1. **Initial Values:** - \( x_0 = 1 \) - \( y_0 = 6 \) 2. **Step 1:** - Calculate \( y_1 \): \[ y_1 = y_0 + h f(x_0, y_0) \] Given \( f(x, y) = 2x - 3y + 1 \): \[ y_1 = 6 + 0.1 \cdot f(1, 6) \] \[ y_1 = 6 + 0.1 \cdot (-15) \] \[ y_1 = 4.5 \] Hence, \( y(1.1) = 4.5 \). 3. **Step 2:** - Calculate \( y_2 \): \[ y_2 = y_1 + h f(x_1, y_1) \] Using \( x_1 = 1.1 \) and \( y_1 = 4.5 \): \[ y_2 = 4.5 + 0.1 \cdot f(1.1, 4.5) \] \[ y_2 = 4.5 + 0.1 \cdot (-10.3) \] \[ y_2 = 3.47 \] Hence, \( y(1.2) = 3.47 \). Thus, using Euler's Method, the value of \( y \) at \( x = 1.2 \) is \( 3.47 \).
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