I cannot figure out the steps to this problem from my homework. How to I find the cotangent inverse of the square root of negative 11? The text in the image is a mathematical expression: \[\cot^{-1} \left( \frac{-1}{\sqrt{3}} \right)\]This expression involves the inverse cotangent (also known as arccotangent) of the fraction $\frac{-1}{\sqrt{3}}$. Inverse trigonometric functions are used to determine the angle whose trigonometric function would yield a particular value. In this case, the function is trying to find the angle whose cotangent is $\frac{-1}{\sqrt{3}}$.

To determine: cot-1-11 Solution :-…

Answered: I cannot figure out the steps to this…

Trigonometry (11th Edition)

11th Edition

ISBN:9780134217437

Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels

Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels

Chapter1: Trigonometric Functions

Section: Chapter Questions

Problem 1RE: 1. Give the measures of the complement and the supplement of an angle measuring 35°.

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I cannot figure out the steps to this problem from my homework. How to I find the cotangent inverse of the square root of negative 11?

The text in the image is a mathematical expression:

\[
\cot^{-1} \left( \frac{-1}{\sqrt{3}} \right)
\]

This expression involves the inverse cotangent (also known as arccotangent) of the fraction $\frac{-1}{\sqrt{3}}$. Inverse trigonometric functions are used to determine the angle whose trigonometric function would yield a particular value. In this case, the function is trying to find the angle whose cotangent is $\frac{-1}{\sqrt{3}}$.

Expert Solution

Step 1

To determine:

$c o t^{- 1} (- \sqrt{11})$

Solution :-

$c o t^{- 1} (x) = \frac{π}{2} - \tan^{- 1} (x) = \frac{π}{2} - \tan^{- 1} (- \sqrt{- 11}) = \frac{π}{2} - (- 1.27795) = \frac{π}{2} + 1.27795 U s e π = 3.14159 = 1.570795 + 1.27795 = 2.848745$

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