College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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please type your solution so that it is easy for to read I have bad eyesight please and thank you
![### Question 7
**Problem:**
An electric field of \(525 \, \text{V/m}\) is desired between two parallel plates that are \(11.0 \, \text{mm}\) apart. How large a voltage should be applied?
**Solution:**
To find the voltage required to produce the desired electric field between the plates, we can use the relationship:
\[ E = \frac{V}{d} \]
Where:
- \(E\) is the electric field (in volts per meter, \(\text{V/m}\)),
- \(V\) is the voltage (in volts, \(\text{V}\)),
- \(d\) is the distance between the plates (in meters, \(\text{m}\)).
Given:
\[ E = 525 \, \text{V/m} \]
\[ d = 11.0 \, \text{mm} = 11.0 \times 10^{-3} \, \text{m} \]
We rearrange the equation to solve for \(V\):
\[ V = E \cdot d \]
Substitute the given values:
\[ V = 525 \, \text{V/m} \times 11.0 \times 10^{-3} \, \text{m} \]
\[ V = 5.775 \, \text{V} \]
**Answer:**
The voltage that should be applied is \(5.775 \, \text{V}\).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa96c07fd-e70d-478a-a514-a2ec6704d773%2F4fc13419-8752-454e-85e7-e7ca0c7f7523%2Fack4w6h_processed.png&w=3840&q=75)
Transcribed Image Text:### Question 7
**Problem:**
An electric field of \(525 \, \text{V/m}\) is desired between two parallel plates that are \(11.0 \, \text{mm}\) apart. How large a voltage should be applied?
**Solution:**
To find the voltage required to produce the desired electric field between the plates, we can use the relationship:
\[ E = \frac{V}{d} \]
Where:
- \(E\) is the electric field (in volts per meter, \(\text{V/m}\)),
- \(V\) is the voltage (in volts, \(\text{V}\)),
- \(d\) is the distance between the plates (in meters, \(\text{m}\)).
Given:
\[ E = 525 \, \text{V/m} \]
\[ d = 11.0 \, \text{mm} = 11.0 \times 10^{-3} \, \text{m} \]
We rearrange the equation to solve for \(V\):
\[ V = E \cdot d \]
Substitute the given values:
\[ V = 525 \, \text{V/m} \times 11.0 \times 10^{-3} \, \text{m} \]
\[ V = 5.775 \, \text{V} \]
**Answer:**
The voltage that should be applied is \(5.775 \, \text{V}\).
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