I am trying to figure out which equations were used to solve this problem. Find Beam Size & Reinforcing Steel (1)A rectangular beam is to be sized with f, = 60,000 psi, f = 3000 psi, and a reinforcement ratio papprox-imately equal to 0.18f,/f,. It is to have a 25-ft simple span and to support a dead load, in addition toits own weight, equal to 2 k/ft and a live load equal to 3 k/ft.SOLUTIONAssume Beam wt= 400 lb/ftW, = (1.2) (2 klf+0.400 klf) + (1.6) (3 klf) = 7.68 klf (k/ft)(7.68 klf)(25 ft)?Mu600 ft-k%3D8(0.18) (3 ksi)= 0.00960 ksiM,= 482.6 psi (from Appendix A, Table A.12)øbd?M,$(482.6 psi)(12 in/ft) (600,000 ft-lb)(0.9) (482.6 psi)bd? :

I'm this question size of rectangular beam is to be calculated. Following are the equations used…

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Engineering

Civil Engineering

I am trying to figure out which equations were used to solve this problem.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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I am trying to figure out which equations were used to solve this problem.

Find Beam Size & Reinforcing Steel (1)
A rectangular beam is to be sized with f, = 60,000 psi, f = 3000 psi, and a reinforcement ratio papprox-
imately equal to 0.18f,/f,. It is to have a 25-ft simple span and to support a dead load, in addition to
its own weight, equal to 2 k/ft and a live load equal to 3 k/ft.
SOLUTION
Assume Beam wt= 400 lb/ft
W, = (1.2) (2 klf+0.400 klf) + (1.6) (3 klf) = 7.68 klf (k/ft)
(7.68 klf)(25 ft)?
Mu
600 ft-k
%3D
8
(0.18) (3 ksi)
= 0.009
60 ksi
M,
= 482.6 psi (from Appendix A, Table A.12)
øbd?
M,
$(482.6 psi)
(12 in/ft) (600,000 ft-lb)
(0.9) (482.6 psi)
bd? :

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