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I am trying to figure out which equations were used to solve this problem.

I am trying to figure out which equations were used to solve this problem.

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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I am trying to figure out which equations were used to solve this problem. 

Find Beam Size & Reinforcing Steel (1) A rectangular beam is to be sized with f, = 60,000 psi, f = 3000 psi, and a reinforcement ratio papprox- imately equal to 0.18f,/f,. It is to have a 25-ft simple span and to support a dead load, in addition to its own weight, equal to 2 k/ft and a live load equal to 3 k/ft. SOLUTION Assume Beam wt= 400 lb/ft W, = (1.2) (2 klf+0.400 klf) + (1.6) (3 klf) = 7.68 klf (k/ft) (7.68 klf)(25 ft)? Mu 600 ft-k %3D 8 (0.18) (3 ksi) = 0.009 60 ksi M, = 482.6 psi (from Appendix A, Table A.12) øbd? M, $(482.6 psi) (12 in/ft) (600,000 ft-lb) (0.9) (482.6 psi) bd? :
Transcribed Image Text:Find Beam Size & Reinforcing Steel (1) A rectangular beam is to be sized with f, = 60,000 psi, f = 3000 psi, and a reinforcement ratio papprox- imately equal to 0.18f,/f,. It is to have a 25-ft simple span and to support a dead load, in addition to its own weight, equal to 2 k/ft and a live load equal to 3 k/ft. SOLUTION Assume Beam wt= 400 lb/ft W, = (1.2) (2 klf+0.400 klf) + (1.6) (3 klf) = 7.68 klf (k/ft) (7.68 klf)(25 ft)? Mu 600 ft-k %3D 8 (0.18) (3 ksi) = 0.009 60 ksi M, = 482.6 psi (from Appendix A, Table A.12) øbd? M, $(482.6 psi) (12 in/ft) (600,000 ft-lb) (0.9) (482.6 psi) bd? :
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