I am having trouble understanding this entire section. First is the particle spinning around the origin o and is L always perpendicular to r and p or is there cases where it won't. I then have trouble understanding everything after "'this L is about 0"
I am having trouble understanding this entire section. First is the particle spinning around the origin o and is L always perpendicular to r and p or is there cases where it won't. I then have trouble understanding everything after "'this L is about 0"
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I am having trouble understanding this entire section. First is the particle spinning around the origin o and is L always perpendicular to r and p or is there cases where it won't. I then have trouble understanding everything after "'this L is about 0"
Transcribed Image Text:law.
(action-caction
0.2 Angular momentum
The angular momentum of a particle with p about point "0"
Z
AL
>у
p
CIF
L = ŕ × p
This is about 0. The angular momentum about some other To is
L = (F-To) × P
• Components:
1
Thus,
Î
У
y
2
Txp=x
z=(ypzzpy) + ŷ(zpx − xpz) + (xpy - ypx)
Px Py Pz|
-
L= (ypz-zpy, zPx - xpz, xpy - ypx)
Or, if we use (x1, x2, x3) and (P1, P2, P3) instead,
L₁ = x2p3x3P2
L2x3P1x1P3
L3x1P2 x2P1
The relations are cyclic.
=
Note: pmv is sometimes called linear momentum.
0.2.1 Example: Constant revolution
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