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I am currently watching a youtube video but i am very confused on how the person found the oxidation state(the red numbers) of the elements

I am currently watching a youtube video but i am very confused on how the person found the oxidation state(the red numbers) of the elements

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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I am currently watching a youtube video but i am very confused on how the person found the oxidation state(the red numbers) of the elements

 

+7 -2 -2 +1 -2 +1 +2 +4 -2 MnO4 (aq) + C₂H5OH(aq) → Mn²+ (aq) + CO₂(g) réduction MnO₂ → Mn²+ MnO₂ → Mn²+ 4 MnO₂ → Mn²+ + 4H₂O 4 MnO₂ + 8 H+ → Mn²+ + 4H₂O MnO₂ + 8 H+ + 5 e¯ → Mn²+ + 4H₂O 12 x (MnO₂ + 8 H+ + 5 e → Mn²+ + 4H₂O) solution acide oxydation C₂H5OH → CO₂ C₂H5OH → 2 CO₂ C,H5OH + 3 H,O) 2 CO, CH5OH +3 H,O > 2 CO, + 12 H C,H,OH + 3 H,O > 2 CO, + 12 H* +12 e (C₂H5OH + 3 H₂O2 CO₂ + 12 H+ + 12 e¯ ) x 5 12 MnO₂ + 96 H+ + 60 e¯ → 12 Mn²+ + 48 H₂O 5 C,H,OH + 15 H,O > 10 CO, + 60 H* + 60 e-
Transcribed Image Text:+7 -2 -2 +1 -2 +1 +2 +4 -2 MnO4 (aq) + C₂H5OH(aq) → Mn²+ (aq) + CO₂(g) réduction MnO₂ → Mn²+ MnO₂ → Mn²+ 4 MnO₂ → Mn²+ + 4H₂O 4 MnO₂ + 8 H+ → Mn²+ + 4H₂O MnO₂ + 8 H+ + 5 e¯ → Mn²+ + 4H₂O 12 x (MnO₂ + 8 H+ + 5 e → Mn²+ + 4H₂O) solution acide oxydation C₂H5OH → CO₂ C₂H5OH → 2 CO₂ C,H5OH + 3 H,O) 2 CO, CH5OH +3 H,O > 2 CO, + 12 H C,H,OH + 3 H,O > 2 CO, + 12 H* +12 e (C₂H5OH + 3 H₂O2 CO₂ + 12 H+ + 12 e¯ ) x 5 12 MnO₂ + 96 H+ + 60 e¯ → 12 Mn²+ + 48 H₂O 5 C,H,OH + 15 H,O > 10 CO, + 60 H* + 60 e-
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And how did she find these numbers

+7 -2 -2 +1 -2 +1 +4 -2 MnO4 (aq) + C₂H5OH(aq) → Mn²+(aq) + CO₂(g) +2 réduction MnO →Mn²+ MnO₂ → Mn²+ MnO₂ → Mn²+ + 4H₂O MnO₂ + 8 H+ → Mn²+ + 4H₂O MnO₂ + 8 H+ +5→Mn²+ + 4H₂O 12 x (MnO₂ + 8 H+ + 5 e¯ → Mn²+ + 4H₂O) solution acide oxydation C₂H5OH → CO₂ C₂H5OH → 2 CO₂ C,H,OH + 3 H,O > 2 CO, C,H5OH + 3 H,O > 2 CO, + 12 H C₂H5OH + 3 H₂O2 CO₂ + 12 H+ +12 e (C₂H5OH + 3 H₂O → 2 CO₂ + 12 H+ + 12 e¯ ) x 5 12 MnO₂ +96 H+ + 60 e¯ → 12 Mn²+ + 48 H₂O 5 C,H,OH + 15 H,O > 10 CO, + 60 H* + 60 e
Transcribed Image Text:+7 -2 -2 +1 -2 +1 +4 -2 MnO4 (aq) + C₂H5OH(aq) → Mn²+(aq) + CO₂(g) +2 réduction MnO →Mn²+ MnO₂ → Mn²+ MnO₂ → Mn²+ + 4H₂O MnO₂ + 8 H+ → Mn²+ + 4H₂O MnO₂ + 8 H+ +5→Mn²+ + 4H₂O 12 x (MnO₂ + 8 H+ + 5 e¯ → Mn²+ + 4H₂O) solution acide oxydation C₂H5OH → CO₂ C₂H5OH → 2 CO₂ C,H,OH + 3 H,O > 2 CO, C,H5OH + 3 H,O > 2 CO, + 12 H C₂H5OH + 3 H₂O2 CO₂ + 12 H+ +12 e (C₂H5OH + 3 H₂O → 2 CO₂ + 12 H+ + 12 e¯ ) x 5 12 MnO₂ +96 H+ + 60 e¯ → 12 Mn²+ + 48 H₂O 5 C,H,OH + 15 H,O > 10 CO, + 60 H* + 60 e
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