A clever witch is social distancing during trick-or-treating by sticking her pumpkin-shaped bucket full of candy on the end of her broomstick. Her broomstick has a length of L = 1.7 m and she holds it horizontally. The broomstick has a mass of 0.80 kg and the pumpkin has a mass of 2.3 kg. The witch holds her hands a distance of d = 0.40 m apart. L d What is the force from the hand on the end of the broom? This is the hand on the left in the figure. FL= ¹5.27 x N What is the force from the hand closer to the middle of the broom? This is the hand on the right in the figure. FR = N

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
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Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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A clever witch is social distancing during trick-or-treating by sticking her pumpkin-shaped bucket full of candy on the end of her broomstick. Her broomstick has a length of L = 1.7 m and she holds it
horizontally. The broomstick has a mass of 0.80 kg and the pumpkin has a mass of 2.3 kg. The witch holds her hands a distance of d = 0.40 m apart.
L
What is the force from the hand on the end of the broom? This is the hand on the left in the figure.
1 5.27
FL =
X N
d
What is the force from the hand closer to the middle of the broom? This is the hand on the right in the figure.
2
N
FR
=
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Transcribed Image Text:A clever witch is social distancing during trick-or-treating by sticking her pumpkin-shaped bucket full of candy on the end of her broomstick. Her broomstick has a length of L = 1.7 m and she holds it horizontally. The broomstick has a mass of 0.80 kg and the pumpkin has a mass of 2.3 kg. The witch holds her hands a distance of d = 0.40 m apart. L What is the force from the hand on the end of the broom? This is the hand on the left in the figure. 1 5.27 FL = X N d What is the force from the hand closer to the middle of the broom? This is the hand on the right in the figure. 2 N FR = Submit Answer View Previous Question Question 4 of 6 View Next Question
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I already tried the answer 5.27 N. I got feedback from my professor explaining that the question gives mass, not forces. (Multiply by constant of 9.8 to find force). They also told me to consider each force independently when finding torques. And consider distance from the pivot point.

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