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i 48 kN/m32 в Анг 81 81 10 kN/m 3 4 P₁ [0KN ↓ ( - 3 B S 12 By Sm 211.667

i 48 kN/m32 в Анг 81 81 10 kN/m 3 4 P₁ [0KN ↓ ( - 3 B S 12 By Sm 211.667

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Am I doing this correct? Determine the support reactions/reactions
48 kN/m32 3 81 2-6671 4 10 kN/m 3 4 P₁ |0KN ↓ 3 B 12 P₁ = 160 P₂=10(8)=80 13 = 1/2 (36) 6) = 152. Bu Sm -725 211.667/ √82+5²- 9.434 tan 1 8 = 32 = 57.995 tan o A T 12 =67.380 SMA=0&+ + -By sin (67.38) (14) - By cos (67.38) (5) +.160 (11) + 803in (57.995) (4) + 80 cos (57.995) (2.s) + 182 sin ($7.995) (2.667). 152 cos (57.995) (1.667) = By = 176. 168 KN
Transcribed Image Text:48 kN/m32 3 81 2-6671 4 10 kN/m 3 4 P₁ |0KN ↓ 3 B 12 P₁ = 160 P₂=10(8)=80 13 = 1/2 (36) 6) = 152. Bu Sm -725 211.667/ √82+5²- 9.434 tan 1 8 = 32 = 57.995 tan o A T 12 =67.380 SMA=0&+ + -By sin (67.38) (14) - By cos (67.38) (5) +.160 (11) + 803in (57.995) (4) + 80 cos (57.995) (2.s) + 182 sin ($7.995) (2.667). 152 cos (57.995) (1.667) = By = 176. 168 KN
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