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I 1--1 What is the average kinetic energy of a molecule of oxygen gas (0₂) at 8 O 16.00 3. 5.061E-21 J D. 6.398E-21 J 5.041E-21 J 5.137E-21 J E. 4.368E-21 J F. 5.862E-21 J A. B. C. 1--1

I 1--1 What is the average kinetic energy of a molecule of oxygen gas (0₂) at 8 O 16.00 3. 5.061E-21 J D. 6.398E-21 J 5.041E-21 J 5.137E-21 J E. 4.368E-21 J F. 5.862E-21 J A. B. C. 1--1

College Physics
College Physics
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ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
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**Educational Website - Physics Section** ### Question on Average Kinetic Energy of Oxygen Molecules #### Multiple Choice Question: **What is the average kinetic energy of a molecule of oxygen gas (O₂) at a temperature of -25°C?** ##### Options: - A. 5.061E-21 J - B. 5.137E-21 J - C. 4.368E-21 J - D. 6.398E-21 J - E. 5.041E-21 J - F. 5.862E-21 J #### Explanation: The question seeks to determine the average kinetic energy of an oxygen molecule at a given temperature (-25°C). The kinetic energy \(E\) of a gas molecule at temperature \(T\) can be determined using the formula: \[ E = \frac{3}{2} k_B T \] Where: - \( k_B \) is the Boltzmann constant \((1.38 \times 10^{-23} \text{ J/K})\) - \( T \) is the temperature in Kelvin First, convert the temperature from Celsius to Kelvin: \[ T(K) = T(°C) + 273.15 \] \[ T = -25 + 273.15 = 248.15 \text{K} \] Now, use the formula to calculate the average kinetic energy: \[ E = \frac{3}{2} \times 1.38 \times 10^{-23} \text{ J/K} \times 248.15 \text{K} \] Selecting the correct value from the provided options ensures a fundamental understanding of thermodynamic principles applied to molecular motion. #### Diagram Analysis: The diagram shows a block containing information about the oxygen molecule: - The symbol \( \mathrm{O} \) - Atomic number \( 8 \) - Atomic mass \( 16.00 \) This visual aids in confirming the properties of the oxygen molecule for the given problem.
Transcribed Image Text:**Educational Website - Physics Section** ### Question on Average Kinetic Energy of Oxygen Molecules #### Multiple Choice Question: **What is the average kinetic energy of a molecule of oxygen gas (O₂) at a temperature of -25°C?** ##### Options: - A. 5.061E-21 J - B. 5.137E-21 J - C. 4.368E-21 J - D. 6.398E-21 J - E. 5.041E-21 J - F. 5.862E-21 J #### Explanation: The question seeks to determine the average kinetic energy of an oxygen molecule at a given temperature (-25°C). The kinetic energy \(E\) of a gas molecule at temperature \(T\) can be determined using the formula: \[ E = \frac{3}{2} k_B T \] Where: - \( k_B \) is the Boltzmann constant \((1.38 \times 10^{-23} \text{ J/K})\) - \( T \) is the temperature in Kelvin First, convert the temperature from Celsius to Kelvin: \[ T(K) = T(°C) + 273.15 \] \[ T = -25 + 273.15 = 248.15 \text{K} \] Now, use the formula to calculate the average kinetic energy: \[ E = \frac{3}{2} \times 1.38 \times 10^{-23} \text{ J/K} \times 248.15 \text{K} \] Selecting the correct value from the provided options ensures a fundamental understanding of thermodynamic principles applied to molecular motion. #### Diagram Analysis: The diagram shows a block containing information about the oxygen molecule: - The symbol \( \mathrm{O} \) - Atomic number \( 8 \) - Atomic mass \( 16.00 \) This visual aids in confirming the properties of the oxygen molecule for the given problem.
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