i - 0 j- 0 k = 0 k - 1 j- 1 k - 0 k = 1 i = 1 j- 0 k - 0 k - 1 j- 1 k - 0 k - 1 done! As before, use variables 'i, 'j', and `k' to match the output. 1 for i in range(2): print("i = " + str(i)) for j in range(2): print(" j - " + str(j)) for k in range (2): print(" k = " + str(k)) 3 4 6 7 print("done!")|
i - 0 j- 0 k = 0 k - 1 j- 1 k - 0 k = 1 i = 1 j- 0 k - 0 k - 1 j- 1 k - 0 k - 1 done! As before, use variables 'i, 'j', and `k' to match the output. 1 for i in range(2): print("i = " + str(i)) for j in range(2): print(" j - " + str(j)) for k in range (2): print(" k = " + str(k)) 3 4 6 7 print("done!")|
C++ for Engineers and Scientists
4th Edition
ISBN:9781133187844
Author:Bronson, Gary J.
Publisher:Bronson, Gary J.
Chapter6: Modularity Using Functions
Section6.4: A Case Study: Rectangular To Polar Coordinate Conversion
Problem 9E: (Numerical) Write a program that tests the effectiveness of the rand() library function. Start by...
Related questions
Question
whats wrong w my code

Transcribed Image Text:i = 0
j- 0
k = 0
k - 1
j = 1
k = 0
k = 1
i = 1
j = 0
k = 0
k = 1
i = 1
k = 0
k = 1
done!
As before, use variables i, j, and k' to match the output.
1 for i in range (2):
print("i = " + str(i))
for j in range(2):
print(" j = " + str(j))
for k in range (2):
print(" k = " + str(k))
3
4
7 print("done!")|
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