Hypothesis Test Results:- **μ**: Mean of variable- **Null Hypothesis (H₀)**: μ = 2.2- **Alternative Hypothesis (Hₐ)**: μ > 2.2| Variable | Sample Mean | Std. Err. | DF | T-Stat | P-value ||----------|-------------|-----------|----|--------|---------|| Length | 2.46821 | 0.276896 | 399| 0.968631| 0.1667 |**Explanation:**- **Sample Mean (2.46821)**: The average measured value from the sample data.- **Standard Error (0.276896)**: The estimated standard deviation of the sample mean, indicating variability.- **Degrees of Freedom (DF = 399)**: The number of independent values in the dataset.- **T-Statistic (0.968631)**: The test statistic used to determine how far the sample mean is from the null hypothesis mean.- **P-value (0.1667)**: The probability of observing the data, or something more extreme, if the null hypothesis is true. A lower P-value suggests stronger evidence against the null hypothesis.

The random variable X follows normal distribution. The given output represents one-sample t-test…

Answered: Hypothesis test results: H: Mean of…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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H0 : =150.00 kPa H1 :>150.00 kPa b) α= 0.01; sample variance : 1300 (freq. table ) sample deviation : 36.0555 (freq. table ) Calculation of Data Mean of the results= = 6700/50 =134 Mid Range of the results= (217.32+46.32)/2= 131.82 Range = (217.32-46.32) = 171 Modal Class= Class 121-145 with the highest frequency of 15 Median of the sorted set of data = 132.25 Mode = there are not clear modes In the samples. Sample variance S o= 1300 Sample deviation: S =36.55
00 N %24 w/ A population has mean u=23 and standard deviation o=7. Round the answers to two decimal places as needed. Part: 0/3 Part 1 of 3 (a) Find the z-score for a population value of 2. The z-score for a population value of 2 is Submit Assignmer Next Part © 2022 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Cen MacBook Air 000 000 F4 F5 F7 F8 F1 F2 F3 %23 2 4. 9- . 44 FO M X
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A data set includes data from 500 random tornadoes. The display from technology available below results from using the tornado lengths (miles) to test the claim that the mean tornado length is greater than 2.3 miles. Use a 0.05 significance level. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim. A Click the icon to view the display from technology. Assuming all conditions for conducting a hypothesis test are met, what are the null and alternative hypotheses? O A. Ho: µ= 2.3 miles H1: µ> 2.3 miles B. Ho: µ= 2.3 miles H,:µ#2.3 miles O C. Ho: µ= 2.3 miles H4: µ< 2.3 miles O D. Ho: µ<2.3 miles H1:µ= 2.3 miles Identify the test statistic. (Round to two decimal places as needed.) Identify the P-value. (Round to three decimal places as needed.) State the final conclusion that addresses the original claim. Ho. There is evidence to support the claim that the mean tornado length is greater than 2.3 miles
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Hypothesis test results: H: Mean of variable Ho : µ= 2.2 HA : H> 2.2 Variable Sample Mean Std. Err. Length DF T-Stat P-value 2.46821 0.276896 399 0.968631 0.1667