hyperconjugation) to solve synthetic problems. (a) Write a detailed, electron-pushing mechanism that accounts for the formation of the organic El products. 'N' CH3 CI CH3 NaOH E1 NaOH PT (b) A lesser-known elimination mechanism is represented here. In this mechanism, the base/nucleophile performs PT in the first step, but the leaving group does not immediately leave, as evidenced by the intermediate. Write a detailed, electron-pushing mechanism to describe this pathway. How does only one (1) organic product forming here compare to the two (2) products formed by E1? CH3 CH3 CH3 CH3 CH3 + HOH + CI CH3 CH3 + HOH

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### Organic Reaction Mechanisms: E1 and Less Common Eliminations

#### Problem 1

(a) Write a detailed, electron-pushing mechanism that accounts for the formation of the organic E1 products.

**Reaction:**

A compound containing a pyridine ring with a chloropropyl side chain (denoted as N—CH2—CH(CH3)—CH2Cl) is treated with sodium hydroxide (NaOH), leading to the formation of two products. The products shown are:

1. A pyridine with a propene group (N—CH=CH2)
2. A pyridine with a 2-methyl-1-propene group (N—C(CH3)=CH2)

Additionally, HOH (water) is produced as a byproduct of the reaction.

**Diagram Explanation:**

- The reaction follows an E1 elimination mechanism where the leaving group (Cl) departs, forming a carbocation intermediate. This intermediate can undergo rearrangement leading to the formation of the observed alkenes.

(b) A lesser-known elimination mechanism is represented here. In this mechanism, the base/nucleophile performs proton transfer (denoted as PT) in the first step, but the leaving group does not immediately leave, as evidenced by the intermediate. Write a detailed, electron-pushing mechanism to describe this pathway. How does only one (1) organic product forming here compare to the two (2) products formed by E1?

**Reaction:**

The starting material is the same pyridine compound with a chloropropyl side chain. In the presence of NaOH, a proton transfer occurs first (indicated as PT), resulting in the intermediary structure where the chlorine remains attached. Eventually, a single product is formed:

1. A pyridine with a propene group (N—CH=CH2)

Water (HOH) and chloride ion (Cl⁻) are released as additional products.

**Diagram Explanation:**

- The mechanism shown indicates that the proton transfer precedes the departure of the leaving group. This results in a distinct intermediate different from the standard E1 elimination, leading to a single product. This lesser-known mechanism illustrates an alternative pathway compared to the formation of two products in the typical E1 reaction.

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Transcribed Image Text:Certainly! Below is the transcription of the text from the image as it might appear on an educational website: --- ### Organic Reaction Mechanisms: E1 and Less Common Eliminations #### Problem 1 (a) Write a detailed, electron-pushing mechanism that accounts for the formation of the organic E1 products. **Reaction:** A compound containing a pyridine ring with a chloropropyl side chain (denoted as N—CH2—CH(CH3)—CH2Cl) is treated with sodium hydroxide (NaOH), leading to the formation of two products. The products shown are: 1. A pyridine with a propene group (N—CH=CH2) 2. A pyridine with a 2-methyl-1-propene group (N—C(CH3)=CH2) Additionally, HOH (water) is produced as a byproduct of the reaction. **Diagram Explanation:** - The reaction follows an E1 elimination mechanism where the leaving group (Cl) departs, forming a carbocation intermediate. This intermediate can undergo rearrangement leading to the formation of the observed alkenes. (b) A lesser-known elimination mechanism is represented here. In this mechanism, the base/nucleophile performs proton transfer (denoted as PT) in the first step, but the leaving group does not immediately leave, as evidenced by the intermediate. Write a detailed, electron-pushing mechanism to describe this pathway. How does only one (1) organic product forming here compare to the two (2) products formed by E1? **Reaction:** The starting material is the same pyridine compound with a chloropropyl side chain. In the presence of NaOH, a proton transfer occurs first (indicated as PT), resulting in the intermediary structure where the chlorine remains attached. Eventually, a single product is formed: 1. A pyridine with a propene group (N—CH=CH2) Water (HOH) and chloride ion (Cl⁻) are released as additional products. **Diagram Explanation:** - The mechanism shown indicates that the proton transfer precedes the departure of the leaving group. This results in a distinct intermediate different from the standard E1 elimination, leading to a single product. This lesser-known mechanism illustrates an alternative pathway compared to the formation of two products in the typical E1 reaction. ---
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