Hydrogen sulfide is an impurity in natural gas that must be removed. One common removal method is called the Claus process, which relies on the reaction: 8H2S(g) + 402 (g)→Ss(t) +8H2O(9) Under optimal conditions the Claus process gives 98% yield of Ss from H2S. Part A If you started with 40.0 grams of H2S and 50.0 grams of O, how many grams of Sg would be produced, assuming 95 % yield? Express your answer using two significant figures.
Hydrogen sulfide is an impurity in natural gas that must be removed. One common removal method is called the Claus process, which relies on the reaction: 8H2S(g) + 402 (g)→Ss(t) +8H2O(9) Under optimal conditions the Claus process gives 98% yield of Ss from H2S. Part A If you started with 40.0 grams of H2S and 50.0 grams of O, how many grams of Sg would be produced, assuming 95 % yield? Express your answer using two significant figures.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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If you started with 40.0 grams of H2SH2S and 50.0 grams of O2O2, how many grams of S8S8 would be produced, assuming 95 %% yield?
Hydrogen sulfide is an impurity in natural gas that must be removed. One common removal method is called the Claus process, which relies on the reaction: 8H2S(g)+4O2(g)→S8(l)+8H2O(g)8H2S(g)+4O2(g)→S8(l)+8H2O(g)
Under optimal conditions, the Claus process gives 98% yield of S8S8 from H2SH2S.

Transcribed Image Text:<Chapter 3 HW
Problem 3.85
17 of 17
II Review | Constants | Periodic Table
Hydrogen sulfide is an impurity in natural gas that must
be removed. One common removal method is called the
Claus process, which relies on the reaction:
8H2S(g) +402 (g)→S8(1) +8H2O(g)
Under optimal conditions the Claus process gives 98%
yield of Sg from H2S.
Part A
If you started with 40.0 grams of H2S and 50.0 grams of O2, how many grams of Sg would be produced, assuming 95 % yield?
Express your answer using two significant figures.
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