Hydrogen is pumped into the closed cylindrical tank such that the mass flow through the tube is m = (0.2p 2) kg/s. Determine the density of the hydrogen within the tank when t = 8s from the time the pump is turned on. Assume that initially there is 0.4kg of hydrogen in the tank. 0.5 m 1.5 m
Hydrogen is pumped into the closed cylindrical tank such that the mass flow through the tube is m = (0.2p 2) kg/s. Determine the density of the hydrogen within the tank when t = 8s from the time the pump is turned on. Assume that initially there is 0.4kg of hydrogen in the tank. 0.5 m 1.5 m
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Solve the first problem, not the example solved. The first question

Transcribed Image Text:Hydrogen is pumped into the closed cylindrical tank such that the mass flow through the tube is
m = (0.2p 2) kg/s. Determine the density of the hydrogen within the tank when t = 8s from the
%3D
time the pump is turned on. Assume that initially there is 0.4kg of hydrogen in the tank.
0.5 m
1.5 m
3

Transcribed Image Text:Hydrogen is pumped into the closed cylindrical tank such that the mass flow through the tube is
m = (0.2p ?) kg/s. Determine the density of the hydrogen within the tank when t=6s from the
time the pump is turned on. Assume that initially there is 0.3kg of hydrogen in the tank.
0.5 m
1.5 m
SOLUTION
Homework #4 Solutions
The fixed control volume considered is shown in Fig. a. This control volume has a
constant volume of
¥ = #(0.5 m)²(1.5 m) = 0.375 m³
The density of the hydrogen within the control volume changes with time, and
therefore contributes to local change. Applying the continuity equation, realizing
that m =
V •dA,
pdý +
dp - m = 0
dt
dp
0.375n- 0.2p = 0
dt
dp
8
dt
15n
Integrating with the initial condition p = po at t=0,
(P 15π 1
-pēdp
8.
Po
dt =
15л 2
t =
8 3
5n
3
- På
4
'Po
4t
p =
57
På) kg/m³
0.8
0.3kg
0.375n m3
kg/m³. Then when t=6s,
Here Po
%3D
4+6
p =
(0.8)
5n
p = 1.40 kg/m³
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