**Chapter 14: Chemical Equilibrium****Problem Statement:**Hydrogen iodide undergoes decomposition according to the equation:\[ 2\text{HI(g)} \rightleftharpoons \text{H}_2\text{(g)} + \text{I}_2\text{(g)} \]The equilibrium constant \( K_p \) at 500 K for this equilibrium is 0.060. Suppose 0.904 mol of HI is placed in a 5.00 L container at 500 K. What is the equilibrium concentration of \(\text{I}_2\text{(g)}\)?\[ R = 0.0821 \, \text{L} \cdot \text{atm}/(\text{K} \cdot \text{mol}) \]**Options:**- A) 0.082 M- B) 0.036 M- C) 0.044 M- D) 1.5 M- E) 0.030 M**Explanation:**To solve this problem, you'll need to use the concept of chemical equilibrium. The equilibrium constant \( K_p \) is given, and you're asked to determine the equilibrium concentration of \(\text{I}_2\text{(g)}\).By setting up an ICE (Initial, Change, Equilibrium) table and applying the equilibrium constant expression, you can solve for the concentration of \(\text{I}_2\text{(g)}\) at equilibrium.

The reaction given is, => 2 HI (g) ------> H2 (g) + I2 (g)…

Hydrogen iodide undergoes decomposition according to the equation 2HI(g) = H2(g) + I>(g) The equilibrium constant K, at 500 K for this equilibrium is 0.060. Suppose 0.904 mol of HI is placed in a 5.00-L container at 500 K. What is the equilibrium concentration of I,(g)? (R= 0.0821 L atm/(K - mol)) O 0.082 M O. 0.036 M O 0.044 M O 1.5 M O 0.030 M

Hydrogen iodide undergoes decomposition according to the equation 2HI(g) = H2(g) + I>(g) The equilibrium constant K, at 500 K for this equilibrium is 0.060. Suppose 0.904 mol of HI is placed in a 5.00-L container at 500 K. What is the equilibrium concentration of I,(g)? (R= 0.0821 L atm/(K - mol)) O 0.082 M O. 0.036 M O 0.044 M O 1.5 M O 0.030 M

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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