Hydrogen iodide decomposes slowly to H2 and I2 at 600 K. The reaction is second order in HI, and the rate constant is 9.7×10−6M−1s−1. If the initial concentration of HI is 0.100 M. What is its molarity after a reaction time of 7.00 days? What is the time (in days) when the HI concentration reaches a value of 0.080 M?
Hydrogen iodide decomposes slowly to H2 and I2 at 600 K. The reaction is second order in HI, and the rate constant is 9.7×10−6M−1s−1. If the initial concentration of HI is 0.100 M. What is its molarity after a reaction time of 7.00 days? What is the time (in days) when the HI concentration reaches a value of 0.080 M?
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Hydrogen iodide decomposes slowly to H2 and I2 at 600 K. The reaction is second order in HI, and the rate constant is 9.7×10−6M−1s−1. If the initial concentration of HI is 0.100 M. What is its molarity after a reaction time of 7.00 days? What is the time (in days) when the HI concentration reaches a value of 0.080 M?
Expert Solution
Step 1
The decomposition of hydrogen iodide is a second-order reaction. The rate constant for the second-order reaction is given by:
where, k = rate constant = 9.7×10−6 M-1s-1
t = time = 7.00 days
[A] = concentration of the reactant after t time =?
[Ao] = initial concentration of the reactant = 0.100 M
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