Hydrogen azide, HN3, decomposes on heating by the following unbalanced equation: HN3 (9) → N2 (9) + H2 (9) If 2.4 atm of pure HN3 (g) is decomposed initially, what is the final total pressure in the reaction container? What are the partial pressures of nitrogen and hydrogen gas? Assume the volume and temperature of the reaction container are constant. Total pressure = atm Partial pressure of N2 atm %3D Partial pressure of H2 = atm

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### Decomposition of Hydrogen Azide

**Chemical Process:**
Hydrogen azide (HN₃) decomposes when heated according to the following unbalanced equation:
\[ \text{HN}_3(g) \rightarrow \text{N}_2(g) + \text{H}_2(g) \]

**Problem Statement:**
If 2.4 atm of pure HN₃(g) is decomposed initially, calculate the final total pressure in the reaction container. Determine the partial pressures of nitrogen (N₂) and hydrogen (H₂) gas. Assume the volume and temperature of the reaction container are constant.

**Calculations:**
- **Total pressure =** \(\_\_\_\_\) atm
- **Partial pressure of N₂ =** \(\_\_\_\_\) atm
- **Partial pressure of H₂ =** \(\_\_\_\_\) atm

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Transcribed Image Text:### Decomposition of Hydrogen Azide **Chemical Process:** Hydrogen azide (HN₃) decomposes when heated according to the following unbalanced equation: \[ \text{HN}_3(g) \rightarrow \text{N}_2(g) + \text{H}_2(g) \] **Problem Statement:** If 2.4 atm of pure HN₃(g) is decomposed initially, calculate the final total pressure in the reaction container. Determine the partial pressures of nitrogen (N₂) and hydrogen (H₂) gas. Assume the volume and temperature of the reaction container are constant. **Calculations:** - **Total pressure =** \(\_\_\_\_\) atm - **Partial pressure of N₂ =** \(\_\_\_\_\) atm - **Partial pressure of H₂ =** \(\_\_\_\_\) atm You can submit your answer or try another version. You have 3 item attempts remaining.
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