Hydrofluoric acid and water react to form fluoride anion and hydronium cation, like this: HF (aq) + H₂O(1)→F (aq) +H₂O* (aq) At a certain temperature, a chemist finds that a 4.5 L reaction vessel containing an aqueous solution of hydrofluoric acid, water, fluoride anion, and hydronium cation at equilibrium has the following composition: amount 1.79 g 615. g F 0.274 g H₂O* 0.487 g Calculate the value of the equilibrium constant for this reaction. Round your answer to 2 significant digits. compound HF H₂O K = 0 X 3

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