HW1_3 problem 3.13/4.1 The 'divide and average' method, an old-time iterative method for approximating the square root of any positive *+ a/x_ Write a MATLAB code (script) to find the square root of 15 number a, can be formulated as x = correct to 4 significant figures and use an fprintf statement to write your final answer to the screen. Hints: 1. Note that a=15 in this case as you are trying to find the square root of 15. Start with an initial value of x. An intelligent initial guess can be x=a/2. 2. Use a while loop to calculate the updated value of x according to the above iterative formula x = **«/x For example, if you start with x=a/2, i.e., x=7.5 initially, then the next updated value of x calculated by your code inside the while loop should be x = *a = (7.5+ 15/7.5)/2=4.75. Thus, at this stage the current value of x is *+a/x 4.75 and the old value of x is 7.5. Accordingly calculate the relative error, e, to properly construct a while loop. 3. Implement the stopping condition for 4 sig figs accuracy and display the last updated value of x as your final answer after you come out of the while loop.
HW1_3 problem 3.13/4.1 The 'divide and average' method, an old-time iterative method for approximating the square root of any positive *+ a/x_ Write a MATLAB code (script) to find the square root of 15 number a, can be formulated as x = correct to 4 significant figures and use an fprintf statement to write your final answer to the screen. Hints: 1. Note that a=15 in this case as you are trying to find the square root of 15. Start with an initial value of x. An intelligent initial guess can be x=a/2. 2. Use a while loop to calculate the updated value of x according to the above iterative formula x = **«/x For example, if you start with x=a/2, i.e., x=7.5 initially, then the next updated value of x calculated by your code inside the while loop should be x = *a = (7.5+ 15/7.5)/2=4.75. Thus, at this stage the current value of x is *+a/x 4.75 and the old value of x is 7.5. Accordingly calculate the relative error, e, to properly construct a while loop. 3. Implement the stopping condition for 4 sig figs accuracy and display the last updated value of x as your final answer after you come out of the while loop.
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Pleae use matlab for this question.

Transcribed Image Text:HW1_3 problem 3.13/4.1
The 'divide and average' method, an old-time iterative method for approximating the square root of any positive
number a, can be formulated as x = 2
x+ a/x
Write a MATLAB code (script) to find the square root of 15
correct to 4 significant figures and use an fprintf statement to write your final answer to the screen.
Hints:
1. Note that a=15 in this case as you are trying to find the square root of 15. Start with an initial value of x. An
intelligent initial guess can be x=a/2.
2. Use a while loop to calculate the updated value of x according to the above iterative formula x = *+ 4/x
For example, if you start with x=a/2, i.e., x=7.5 initially, then the next updated value of x calculated by your code
inside the while loop should be x = *+a/x
4.75 and the old value of x is 7.5. Accordingly calculate the relative error, e, to properly construct a while loop.
= (7.5+ 15/7.5)/2=4.75. Thus, at this stage the current value of x is
3. Implement the stopping condition for 4 sig figs accuracy and display the last updated value of x as your final answer after
you come out of the while loop.
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