HW1.2 – Find the values in the Figure.1 if the current through the 35 Q resistor is 5 A.162ww(a) the voltage VA,SA:30Ω(b) the voltage V8 ,15Ω3(e) the power Ps.102352Ps(c) the current Is,30Ω60 Ω(e) the power Pg.Figure.2HW1.3 – Calculate the voltages Vo and Vab , the currents io and ix, the power of Psı in the Figure.3via Ohm's Law, KVL, and KCL. The voltage sources of the circuit are Vsi = 250 Volt, Vs2= 50 Volt.70252170iotVsi5.ixVszVab480Figure.3wwwwww

As per the guidelines of Bartleby we supposed to answer first three subparts of question HW1.2 for…

HW1.2 – Find the values in the Figure.1 if the current through the 35 Q resistor is 5 A. 162 ww (a) the voltage VA, 5A 30Ω (b) the voltage Vs, 15Ω% (e) the power Ps. 10Ω 352 Ps (c) the current Is, 30Ω 60 Ω (e) the power Pg. Ligura ? ww ww ww ww ww

HW1.2 – Find the values in the Figure.1 if the current through the 35 Q resistor is 5 A. 162 ww (a) the voltage VA, 5A 30Ω (b) the voltage Vs, 15Ω% (e) the power Ps. 10Ω 352 Ps (c) the current Is, 30Ω 60 Ω (e) the power Pg. Ligura ? ww ww ww ww ww

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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The conversion of electrical energy to heat energy is known as electric heating. The heating system that converts the electrical energy to heat energy for various application is called electrical heating unit. Electricity is employed as the firing mechanism in electric heating systems, which transforms electric current to heat. Electric heaters have heating elements in the form of electric resistors.

Question

HW1.2 – Find the values in the Figure.1 if the current through the 35 Q resistor is 5 A.
162
ww
(a) the voltage VA,
SA
:30Ω
(b) the voltage V8 ,
15Ω3
(e) the power Ps.
102
352
Ps
(c) the current Is,
30Ω
60 Ω
(e) the power Pg.
Figure.2
HW1.3 – Calculate the voltages Vo and Vab , the currents io and ix, the power of Psı in the Figure.3
via Ohm's Law, KVL, and KCL. The voltage sources of the circuit are Vsi = 250 Volt, Vs2= 50 Volt.
70
252
170
iot
Vsi
5.ix
Vsz
Vab
480
Figure.3
ww
ww
ww

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