apvQ1-Derive the differential form of the continuity equation V.J+ = 0 using Maxwell's Equations.atSolution: From Ampere's law we haveaDV x H = J+atTaking the divergence of both sidesV. (V x H) = V.J+V.7 (210) = √V.J + V.atUsing the vector identity ofV. (V x A) = 0And Gauss law for electric fieldV.D = PuWe get that the left-hand side equals Zero and we arrange the right-hand side toapv0 = V.J+aatV.D = V.J+atHW1- Derive the integral forms of Maxwell's equations and the continuity equation from the differentialform.V.D

To Find : Maxwell's equation in integral form from there differential form. Continuity equation in…

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HW1- Derive the integral forms of Maxwell's equations and the continuity equation from the differential form.