(hw) A block with mass M rests on a frictionless surface and is connected to a horizontal spring of force constant k. The other end of the spring is attached to a wall. A second block with mass m rests on top of the first of the first block. There coefficient of static friction between the blocks is Ms (a) Draw free-body diagram. (b) Find the maximum amplitude of the oscillation such that the top block will not slip on the bottom block. m kummimmi M M

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Chapter5: Energy
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Please show free body diagram 

a and b

### Problem Statement

A block with mass \( M \) rests on a frictionless surface and is connected to a horizontal spring of force constant \( k \). The other end of the spring is attached to a wall. A second block with mass \( m \) rests on top of the first block. The coefficient of static friction between the blocks is \( \mu_s \).

#### Tasks:
1. **Draw a free-body diagram.**
2. **Find the maximum amplitude of the oscillation such that the top block will not slip on the bottom block.**

### Free-Body Diagram

Below is the description of the free-body diagram shown in the image:

1. The figure depicts two blocks, one with mass \( M \) (bottom block) and one with mass \( m \) (top block).
2. The bottom block \( M \) is connected to a spring with spring constant \( k \).
3. The surface on which block \( M \) rests is frictionless.
4. The coefficient of static friction between the blocks is denoted by \( \mu_s \).
5. The top block \( m \) is subjected to frictional force due to the coefficient of static friction \( \mu_s \), preventing it from slipping off the bottom block during oscillations.

### Detailed Explanation of the Diagram:

- **Spring:** A horizontal spring is attached to a wall at one end and to the bottom block \( M \) at the other end. The spring is shown in a compressed or stretched state, indicating its oscillatory motion potential.
- **Blocks:** The bottom block \( M \) is in direct contact with the frictionless surface, whereas the top block \( m \) is placed on the bottom block \( M \). 
- **Friction:** The static friction between blocks \( m \) and \( M \) is represented by \( \mu_s \), preventing the top block from slipping when oscillated horizontally.

### Mathematical Formulation

#### (a) Free-Body Diagram:
- **For the top block (m):**
  - Weight (\( mg \)) acts downward.
  - Normal force (\( N \)) acts upward.
  - Frictional force (\( f = \mu_s \cdot N \)) acts horizontally to the left or right, opposing motion relative to the bottom block.

- **For the bottom block (M):**
  - Weight (\( Mg \)) and the normal reaction from
Transcribed Image Text:### Problem Statement A block with mass \( M \) rests on a frictionless surface and is connected to a horizontal spring of force constant \( k \). The other end of the spring is attached to a wall. A second block with mass \( m \) rests on top of the first block. The coefficient of static friction between the blocks is \( \mu_s \). #### Tasks: 1. **Draw a free-body diagram.** 2. **Find the maximum amplitude of the oscillation such that the top block will not slip on the bottom block.** ### Free-Body Diagram Below is the description of the free-body diagram shown in the image: 1. The figure depicts two blocks, one with mass \( M \) (bottom block) and one with mass \( m \) (top block). 2. The bottom block \( M \) is connected to a spring with spring constant \( k \). 3. The surface on which block \( M \) rests is frictionless. 4. The coefficient of static friction between the blocks is denoted by \( \mu_s \). 5. The top block \( m \) is subjected to frictional force due to the coefficient of static friction \( \mu_s \), preventing it from slipping off the bottom block during oscillations. ### Detailed Explanation of the Diagram: - **Spring:** A horizontal spring is attached to a wall at one end and to the bottom block \( M \) at the other end. The spring is shown in a compressed or stretched state, indicating its oscillatory motion potential. - **Blocks:** The bottom block \( M \) is in direct contact with the frictionless surface, whereas the top block \( m \) is placed on the bottom block \( M \). - **Friction:** The static friction between blocks \( m \) and \( M \) is represented by \( \mu_s \), preventing the top block from slipping when oscillated horizontally. ### Mathematical Formulation #### (a) Free-Body Diagram: - **For the top block (m):** - Weight (\( mg \)) acts downward. - Normal force (\( N \)) acts upward. - Frictional force (\( f = \mu_s \cdot N \)) acts horizontally to the left or right, opposing motion relative to the bottom block. - **For the bottom block (M):** - Weight (\( Mg \)) and the normal reaction from
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