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HW 4.2 What is AU of 1 mole of O2(g) when it is heated from 298 K to 500 K, if the volume of gas is forced to be constant? Given: molar heat capacity of O2(g) at this temperature range is Cy = 17.23 + 13.61×10T – 42.55 × 10-7T² (Answer: AU = 4.4 kJ)

HW 4.2 What is AU of 1 mole of O2(g) when it is heated from 298 K to 500 K, if the volume of gas is forced to be constant? Given: molar heat capacity of O2(g) at this temperature range is Cy = 17.23 + 13.61×10T – 42.55 × 10-7T² (Answer: AU = 4.4 kJ)

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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HW 4.2 What is AU of 1 mole of O2(g) when it is heated from 298 K to 500 K, if the volume of gas is forced to be constant? Given: molar heat capacity of O2(g) at this temperature range is Cy = 17.23 + 13.61×10-3T – 42.55 x 10-7T? %3D (Answer: AU = 4.4 kJ) %3D
Transcribed Image Text:HW 4.2 What is AU of 1 mole of O2(g) when it is heated from 298 K to 500 K, if the volume of gas is forced to be constant? Given: molar heat capacity of O2(g) at this temperature range is Cy = 17.23 + 13.61×10-3T – 42.55 x 10-7T? %3D (Answer: AU = 4.4 kJ) %3D
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