hub blade R 3R Problem 1. An aircraft's propeller consists of a rigid hub of radius R and a flexible tapered blade of length 3R that has density p (kg/m³). The propeller is rotating about the center of the hub with a steady angular velocity », thereby creating an effective axial distributed force in the blade. Neglect forces due to gravity. The cross sectional area distribution of the blade is A(r), defined as A₁ if R

Precision Machining Technology (MindTap Course List)
2nd Edition
ISBN:9781285444543
Author:Peter J. Hoffman, Eric S. Hopewell, Brian Janes
Publisher:Peter J. Hoffman, Eric S. Hopewell, Brian Janes
Chapter8: Computer Numerical Control
Section8.1: Cnc Basics
Problem 3RQ: Briefly describe a ball screw and a linear guide.
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hub
blade
R
3R
Transcribed Image Text:hub blade R 3R
Problem 1.
An aircraft's propeller consists of a rigid hub of radius R and a flexible tapered
blade of length 3R that has density p (kg/m³). The propeller is rotating about the center of the hub
with a steady angular velocity », thereby creating an effective axial distributed force in the blade.
Neglect forces due to gravity. The cross sectional area distribution of the blade is A(r), defined as
A₁ if R<r< 4R
A(r) = (5) A₁ =
R
(a) Write down the expression for body force due to rotational acceleration.
(b) In the 1D equilibrium equation derived in class, the area of cross section was constant.
Show that the 1D equilibrium equation for the case of a changing cross sectional area is
d(σA)
dr
+ fA = 0.
(c) Write down the boundary conditions for the problem.
(d) Find the axial stress distribution, σ (r).
Transcribed Image Text:Problem 1. An aircraft's propeller consists of a rigid hub of radius R and a flexible tapered blade of length 3R that has density p (kg/m³). The propeller is rotating about the center of the hub with a steady angular velocity », thereby creating an effective axial distributed force in the blade. Neglect forces due to gravity. The cross sectional area distribution of the blade is A(r), defined as A₁ if R<r< 4R A(r) = (5) A₁ = R (a) Write down the expression for body force due to rotational acceleration. (b) In the 1D equilibrium equation derived in class, the area of cross section was constant. Show that the 1D equilibrium equation for the case of a changing cross sectional area is d(σA) dr + fA = 0. (c) Write down the boundary conditions for the problem. (d) Find the axial stress distribution, σ (r).
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