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h(t) = √t+6-2 (a) h(-6)) 1 5. f(x) = x² - 4 (a) f(2)) 6. f(x) = √3x + 5, x² +2, (a) f(-2)) x < -1 x ≥ −1 (b) h(3) (b) f(x + 2) (b) f(0) (c) h(x-6) (c) f(0) (c) f(-1)

h(t) = √t+6-2 (a) h(-6)) 1 5. f(x) = x² - 4 (a) f(2)) 6. f(x) = √3x + 5, x² +2, (a) f(-2)) x < -1 x ≥ −1 (b) h(3) (b) f(x + 2) (b) f(0) (c) h(x-6) (c) f(0) (c) f(-1)

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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In Exercises 1-8, evaluate the function at each specified value of the independent variable and simplify
h(t) = √t+ 6-2 (a) h(-6)) 1 5. f(x) = x² - 4 (a) f(2)) 6. f(x) = 8. 7. f(x) = [3x+5, x < -1 x² + 2, x ≥ −1 (a) f(-2)) X x-6 (a) f(x + 1)) [x²-3, x≤-1 x + 4, x>-1 g(x) = (a) g(-2)) (b) h(3) (b) f(x + 2) (b) f(0) (b) f(0) (b) g(3) (c) h(x-6) (c) f(0) (c) f(-1) (c) ƒ(6) (c) g(-4)
Transcribed Image Text:h(t) = √t+ 6-2 (a) h(-6)) 1 5. f(x) = x² - 4 (a) f(2)) 6. f(x) = 8. 7. f(x) = [3x+5, x < -1 x² + 2, x ≥ −1 (a) f(-2)) X x-6 (a) f(x + 1)) [x²-3, x≤-1 x + 4, x>-1 g(x) = (a) g(-2)) (b) h(3) (b) f(x + 2) (b) f(0) (b) f(0) (b) g(3) (c) h(x-6) (c) f(0) (c) f(-1) (c) ƒ(6) (c) g(-4)
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