Hs is burned in an engine with a fuel-rich air-fuel ratio Dry analysis of the exhaust gives the following volume percents: CO, 14.95%, C,H, 0.75%, CO 0%. H3 = 0%, O, 0%, with the rest being N. Higher heating value of this fuel is Quuv = 46.9 MJ/kg. Write the balanced chemical equation for one mole of this fuel at these conditions Calculate: %3D %3D a) Air-fuel ratio. b) Equivalence ratio. (e) Lower heating value of fuel. [MJ/kg] d) Energy released when one kg of this fuel is burned in the engine with a combustion efficiency of 98%. [MJ]

Hs is burned in an engine with a fuel-rich air-fuel ratio Dry analysis of the exhaust gives the following volume percents: CO, 14.95%, C,H, 0.75%, CO 0%. H3 = 0%, O, 0%, with the rest being N. Higher heating value of this fuel is Quuv = 46.9 MJ/kg. Write the balanced chemical equation for one mole of this fuel at these conditions Calculate: %3D %3D a) Air-fuel ratio. b) Equivalence ratio. (e) Lower heating value of fuel. [MJ/kg] d) Energy released when one kg of this fuel is burned in the engine with a combustion efficiency of 98%. [MJ]

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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