hree resistors having resis ces n₁ = 1.12 R22.62 N and R3 = 4.73 2 respectively, are onnected in series to a 27.7 V battery that has egligible internal resistance. or related problem-solving tips and strategies, you ay want to view a Video Tutor Solution of resistor network. Tem 2: significant figures than required for this part. Part E V₁ = IR₁ = (3.05A) (1.7202) = 5.25V. V₂ = IR₂ = (3.05A) (2.620) = 8.00V. V3 = IR3 = (3.05A) (4.73M) = 14.4V. Note that V₁ + V₂ + V3 = 27.7V. answer 6.001 v was either founded ame Find the power dissipated in each resistor. Express your answers in watts separated by commas. PR₁ PR₂ PR₁ = " 5 ΑΣΦ Submit Previous Answers Request Answer ? W

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Chapter1: Units, Trigonometry. And Vectors
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Three resistors having resistances of R₁ = 1.72
R₂ = 2.62 and R3 = 4.73
respectively, are
"
connected in series to a 27.7 V battery that has
negligible internal resistance.
For related problem-solving tips and strategies, you
may want to view a Video Tutor Solution of
A resistor network.
Submit
Part E
Previous Answers
Correct
Term 2: Correct answer is shown. Your answer 8.001 V was either rounded differently or
significant figures than required for this part.
=
V₁ = IR₁ = (3.05A) (1.720) = 5.25V. V₂ = IR2 = (3.05A) (2.62N) = 8.00V.
V3 = IR3 = (3.05A) (4.73N) = 14.4V.
Note that V₁ + V₂ + V3 = 27.7V.
Find the power dissipated in each resistor.
Express your answers in watts separated by commas.
PR₁ PR₂, PR3
"
=
[Π ΑΣΦ
Submit Previous Answers Request Answer
?
W
Transcribed Image Text:Three resistors having resistances of R₁ = 1.72 R₂ = 2.62 and R3 = 4.73 respectively, are " connected in series to a 27.7 V battery that has negligible internal resistance. For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of A resistor network. Submit Part E Previous Answers Correct Term 2: Correct answer is shown. Your answer 8.001 V was either rounded differently or significant figures than required for this part. = V₁ = IR₁ = (3.05A) (1.720) = 5.25V. V₂ = IR2 = (3.05A) (2.62N) = 8.00V. V3 = IR3 = (3.05A) (4.73N) = 14.4V. Note that V₁ + V₂ + V3 = 27.7V. Find the power dissipated in each resistor. Express your answers in watts separated by commas. PR₁ PR₂, PR3 " = [Π ΑΣΦ Submit Previous Answers Request Answer ? W
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