Refer to Figure 8.13. Given; the width of the dam, B = 6 m; length of the dam, L = 120 m; S 3 m; T' = 6 m; x 2.4 m; and H,- H, = 5 m. If the hydraulic conductivity of the permeable layer is 0.008 cm/sec, estimate the seepage un- der the dam (Q) in m/day.
Refer to Figure 8.13. Given; the width of the dam, B = 6 m; length of the dam, L = 120 m; S 3 m; T' = 6 m; x 2.4 m; and H,- H, = 5 m. If the hydraulic conductivity of the permeable layer is 0.008 cm/sec, estimate the seepage un- der the dam (Q) in m/day.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
Related questions
Question
please explain every step
![H = H - H;
T'
Sheet pile
Impervious layer](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1aa9986f-3b33-47af-a665-93a152d08690%2F64d58b28-8a04-4167-820f-da17e0bd4d67%2Fyrfzvmn_processed.jpeg&w=3840&q=75)
Transcribed Image Text:H = H - H;
T'
Sheet pile
Impervious layer
![Refer to Figure 8.13. Given; the width of the dam, B = 6 m; length of the dam,
L = 120 m; S = 3 m; T' = 6 m; x 2.4 m; and H,- H, = 5 m. If the hydraulic
conductivity of the permeable layer is 0.008 cm/sec, estimate the seepage un-
der the dam (Q) in m/day.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1aa9986f-3b33-47af-a665-93a152d08690%2F64d58b28-8a04-4167-820f-da17e0bd4d67%2F3f3wnjg_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Refer to Figure 8.13. Given; the width of the dam, B = 6 m; length of the dam,
L = 120 m; S = 3 m; T' = 6 m; x 2.4 m; and H,- H, = 5 m. If the hydraulic
conductivity of the permeable layer is 0.008 cm/sec, estimate the seepage un-
der the dam (Q) in m/day.
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Follow-up Questions
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Follow-up Question
can you explain how to get the value of q/kH from the diagram?
![유 음
T'
t oy -
두 - (두
+1.00
t b.구5
t0.50
+0:25
+0.00
according to the diagram;
the value of qkH#0.378
q=0.378 kH](https://content.bartleby.com/qna-images/question/1aa9986f-3b33-47af-a665-93a152d08690/e9062a54-777c-4d47-b16f-fe5fba18c6da/18n6anj_thumbnail.jpeg)
Transcribed Image Text:유 음
T'
t oy -
두 - (두
+1.00
t b.구5
t0.50
+0:25
+0.00
according to the diagram;
the value of qkH#0.378
q=0.378 kH
Solution
Follow-up Question
how'd you get the value of q/kH based on the diagram?
Solution
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