Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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How would you solve this expression using Order Of Operations? (PEMDAS)
![The expression in the image is a mathematical equation presented as a fraction. Below is a detailed transcription and explanation:
The numerator of the fraction is:
\[
-\frac{3}{4} \left[ -7(-4^2 + 8) \right] - \sqrt[3]{729}
\]
1. The term \(-4^2 + 8\) involves squaring \(-4\) (resulting in 16) and then adding 8.
2. This part \(-7(-4^2 + 8)\) is multiplied by \(-7\).
3. The resulting expression of the multiplication \(-\frac{3}{4}\) is multiplied by \(-\frac{3}{4}\).
4. The cube root of 729 is subtracted from the entire value obtained above.
The denominator of the fraction is:
\[
\left( \frac{1}{-2} \right)^3
\]
1. This is the cube of the fraction \(\frac{1}{-2}\).
This algebraic expression can be used for solving complex arithmetic problems and can be further simplified for educational purposes to understand the principles of arithmetic operations, including squaring numbers, handling negative signs, and finding roots.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F85230509-ff84-48f3-b749-1ba066c957d1%2F4bc470a0-f32b-41a9-82d7-331f7c02246d%2Fzgi086f_processed.png&w=3840&q=75)
Transcribed Image Text:The expression in the image is a mathematical equation presented as a fraction. Below is a detailed transcription and explanation:
The numerator of the fraction is:
\[
-\frac{3}{4} \left[ -7(-4^2 + 8) \right] - \sqrt[3]{729}
\]
1. The term \(-4^2 + 8\) involves squaring \(-4\) (resulting in 16) and then adding 8.
2. This part \(-7(-4^2 + 8)\) is multiplied by \(-7\).
3. The resulting expression of the multiplication \(-\frac{3}{4}\) is multiplied by \(-\frac{3}{4}\).
4. The cube root of 729 is subtracted from the entire value obtained above.
The denominator of the fraction is:
\[
\left( \frac{1}{-2} \right)^3
\]
1. This is the cube of the fraction \(\frac{1}{-2}\).
This algebraic expression can be used for solving complex arithmetic problems and can be further simplified for educational purposes to understand the principles of arithmetic operations, including squaring numbers, handling negative signs, and finding roots.
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