How would you prepare 70.0 mL of 0.400 M HNO3 from a stock solution of 4.00 M HNO3? What volume (in mL) of the 4.00 M HNO3 solution will you need? Round your answer to 3 significant digits.

Q: You wish to make a 0.354 M hydroiodic acid solution from a stock solution of 12.0 M hydroiodic acid.…

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Q: stock solution of Mg(NO3)2 is available to prepare solutions that are more dilute. Calculate the…

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Q: In the laboratory you dissolve 12.0 g of aluminum nitrate in a volumetric flask and add water to a…

A: Molar mass of Al(NO3)3 = 213 g/ mol Given mass of Al(NO3)3 = 12.0 g  Moles of Al(NO3)3 = Mass /…

Q: In the laboratory, a student dilutes 16.8 mL of a 6.40 M hydrochloric acid solution to a total…

A: • Before dilution,Concentration of HCl solution (M1) = 6.40 MVolume of HCl solution (V1) = 16.8 mL•…

Q: You wish to make a 0.374 M perchloric acid solution from a stock solution of 12.0 M perchloric acid.…

A: Given a stock solution of 12.0 M perchloric acid. We wish to prepare 50 mL of 0.374 M diluted…

Q: How many milliliters of a 0.53 M Co2+ solution are required to prepare 227 mL of a 0.021 M Co2+…

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Q: You have a stock solution of 9.00 M nitric acid. How many mL of the stock solution would you need to…

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Q: In the laboratory, a student dilutes 22.9 mL of a 11.9 M nitric acid solution to a total volume of…

A: Moles of solute remain constant during dilution. Moles of solute = molarity x volume of solution…

Q: 6.0 M HCl solution must be diluted to 0.50 M. If the diluted solution has a total volume of 300.0…

A: Assuming V mL of the concentrated HCl is needed Since the process is dilution  hence the moles of…

Q: What mass of Fe(NO3)3 do you need to prepare 150.00 mL of 0.550 M solution? Make sure all of your…

A: Mole is a standard unit for measuring large quantities of very small entities such as…

Q: You wish to make a 0.115 M perchloric acid solution from a stock solution of 3.00 M perchloric acid.…

A: The given problem can be solved by using the formula given below as; M1 V1 = M2 V2…

Q: You wish to make a 0.399 M nitric acid solution from a stock solution of 6.00 M nitric acid. How…

A: The process of dilution is defined as the process in which a solution with a lower concentration is…

Q: A student needs exactly 25.0 mL of a 1.5M solution of NaOH (molar mass: 40.00 g/mol). They have…

A: Given: Concentration of NaOH = 1.5 M Volume of solution required = 25.0 mL = 0.025 L…

Q: You are making 2,000 mL of a 1.6 M KBr solution.  How many moles of KBr will be added?  How many…

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Q: You wish to make a 0.149 M hydrochloric acid solution from a stock solution of 6.00 M hydrochloric…

A: Calculate the number of moles of HCl in the final dilute solution of 0.149 M and 50.0 milliliters.

Q: Calculate the molarity of 126.2  mL of diluted NaOH solution prepared from 16.6 mL of 6.9  M NaOH…

A: To solve this problem we will use the formula of dilution law .  According to this law  M1V1 = M2V2…

Q: In the laboratory, a student dilutes 17.8 mL of a 8.25 M hydroiodic acid solution to a total volume…

A: Given: Concentration of concentrated HI solution = 8.25 M Volume of concentrated HI solution = 17.8…

Q: Calculate the volume (in mL) of a 1.205M stock NaOH solution needed to prepare 250.0 mL of a 0.1157M…

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Q: A student is asked to prepare 250 mL of a 0.0104 M NaCl solution. The student found a stock bottle…

A: Given: A student has to prepare 250 mL of 0.0104 M NaCl solution using 34.7 mL of 0.0723 M NaCl…

Q: You wish to make a 0.273 M perchloric acid solution from a stock solution of 3.00 M perchloric acid.…

A: Given information is,

Q: You wish to make a 0.192 M perchloric acid solution from a stock solution of 12.0 M perchloric acid.…

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Q: What volume of 0.218 M KMnO4 solution is needed to prepare 503. mL of 0.0151 M KMnO4? Enter your…

A: The equation is, M1V1 = M2V2

Q: A laboratory assistant needs to prepare 166 mL of 0.152 M CaCl2 solution. How many grams of calcium…

A: Given  Volume to prepare CaCl2=166 mL Concentration of CaCl2= 0.152 M The gram of CaCl2 required has…

Q: In the laboratory a student combines 46.6 mL of a 0.307 M iron(III) fluoride solution with 22.4 mL…

A: GIVEN: The Volume of Iron(III) Fluoride = 46.6 mL The concentration of Iron(III) Fluoride =0.307 M…

Q: 227 mL of a 3.2 M solution of KBr is diluted to 731 mL.  What is the new concentration of the…

A: The process of dilution is defined as the process in which a solution with a lower concentration is…

Q: A stock solution of 30.0 mL of a 12 M HNO3 solution was acquired. If 2 mL of the stock solution was…

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Q: You have a stock solution of 5.0 M NaCl. If you want to make 300.0 mL of 0.150 M NaCl, how many…

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Q: You wish to make a 0.338 M hydrochloric acid solution from a stock solution of 12.0 M hydrochloric…

A: Concentrated solutions upon addition of water gets diluted to lower concentrations. The dilution of…

Q: What volume of 0.252 M potassium hydroxide solution is required to completely neutralize 0.0106…

A: Chemical ReactionH3PO4 +3 KOH →K3PO4  + 3H2OMolarity of KOH = 0.252 MMoles of Phosphoric Acid =…

Q: You need to make 200.mL of a 0.35 M NaCl solution of sodium chloride. You start with a 1.0 M…

A: Molarity (M) is the amount of a substance in a certain volume of solution.  Molarity is defined as…

Q: How many milliliters of 11.5 M HCl(aq)11.5 M HCl(aq) are needed to prepare 155.0 mL155.0 mL of 1.00

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Q: You have a standard stock 1.65 M solution of NaH2PO4. For an experiment you require 236 mL of a 0.82…

A: Given that -  Molarity of the stock NaH2PO4 Solution = 1.65 M  Molarity of diluted NaH2PO4 solution…

Q: What is the concentration of methanol in a solution prepared by combining 7.97 mL of a 3.849 M…

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Q: You wish to make a 0.382 M hydrochloric acid solution from a stock solution of 12.0 M hydrochloric…

A: The objective of this question is to find out the volume of the concentrated hydrochloric acid that…

Q: A 5.00 M NaCl “stock” solution is available. How would 300 mL of a 0.100 M NaCl solution be…

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Q: What volume of 2.50 M NaOH would be required to prepare 250.0 mL of 0.150 M NaOH?

A: Here, we have to find the volume of 2.50 M NaOH that would be required to prepare 250.0 mL of 0.150…

Q: What volume, in millileters, of 4.0 M NaOH is needed to prepare 145mL of .45 M NaOH?   16mL…

A: We can use equation of dilution for solving this problem. That is, M1V1 = M2V2

Solutions

Solutions can be considered as homogeneous mixtures which contain two or more than two chemical substances. The chemical substance which is the greater part is defined as solvent. And the chemical substance that is dissolved in a solvent is referred to as solute. Solution chemistry plays an important role in chemistry since it supports many commercial applications of solutions.