how would you figure this out?BINARY COMPOUNDS T01/S04A compound containing only carbon and oxygen is 42.88 % by weight carbon and 57.14 % by weight oxygen. Determine its empirical formula.Molar Mass (g/mol)C 12.011O 15.999
how would you figure this out?
BINARY COMPOUNDS T01/S04
A compound containing only carbon and oxygen is 42.88 % by weight carbon and 57.14 % by weight oxygen. Determine its empirical formula.
Molar Mass (g/mol)
C 12.011
O 15.999
Determination of empirican formula pf a compound from percentage
Given here, binary compound of C and O
C = 42.88% and O = 57.14%
Let the percentages be in grams.
divide these by the atomic masses of C (12 g/mol) and O (16 g/mol)
C = 42.88 g/12 g/mol = 3.6
O = 57.14 g/16 g/mol = 3.6
Divide these by factor 3.6,
C = 3/6/3.6 = 1
O = 3.6/3.6 = 1
So,
The empirical formula of the compound = CO
Molar mass of the compound = (12.011 + 15.999) g/mol
= 28.010 g/mol
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