How would the solubility of BaF2 change with the addition of a strong acid? Explain your answer.

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**Question 2: Solubility of BaF₂ with the Addition of a Strong Acid**

*How would the solubility of BaF₂ change with the addition of a strong acid? Explain your answer.*

When explaining the effect of adding a strong acid on the solubility of barium fluoride (BaF₂), consider the following chemical principles:

1. **Dissolution Reaction:** BaF₂ dissolves in water according to the following equilibrium reaction:
   \[
   \text{BaF}_2(s) \rightleftharpoons \text{Ba}^{2+}(aq) + 2\text{F}^-(aq)
   \]

2. **Addition of a Strong Acid:** When a strong acid (e.g., HCl) is added to the solution, it dissociates completely into H⁺ and the corresponding anion (Cl⁻ in the case of HCl). The increase in H⁺ ions in the solution will react with F⁻ ions to form HF (hydrofluoric acid):
   \[
   \text{H}^+(aq) + \text{F}^-(aq) \rightarrow \text{HF}(aq)
   \]

3. **Le Chatelier's Principle:** According to Le Chatelier's Principle, the removal of F⁻ ions (due to the formation of HF) shifts the dissolution equilibrium of BaF₂ to the right, causing more BaF₂ to dissolve in an attempt to restore the equilibrium concentration of F⁻ ions.

4. **Increased Solubility:** Therefore, with the decrease in F⁻ concentration due to the formation of HF, more BaF₂ will dissolve, thus increasing its solubility in the presence of a strong acid.

In summary, the addition of a strong acid to a solution containing BaF₂ will increase its solubility due to the removal of F⁻ ions from the solution, shifting the equilibrium toward the dissolution of more BaF₂.
Transcribed Image Text:**Question 2: Solubility of BaF₂ with the Addition of a Strong Acid** *How would the solubility of BaF₂ change with the addition of a strong acid? Explain your answer.* When explaining the effect of adding a strong acid on the solubility of barium fluoride (BaF₂), consider the following chemical principles: 1. **Dissolution Reaction:** BaF₂ dissolves in water according to the following equilibrium reaction: \[ \text{BaF}_2(s) \rightleftharpoons \text{Ba}^{2+}(aq) + 2\text{F}^-(aq) \] 2. **Addition of a Strong Acid:** When a strong acid (e.g., HCl) is added to the solution, it dissociates completely into H⁺ and the corresponding anion (Cl⁻ in the case of HCl). The increase in H⁺ ions in the solution will react with F⁻ ions to form HF (hydrofluoric acid): \[ \text{H}^+(aq) + \text{F}^-(aq) \rightarrow \text{HF}(aq) \] 3. **Le Chatelier's Principle:** According to Le Chatelier's Principle, the removal of F⁻ ions (due to the formation of HF) shifts the dissolution equilibrium of BaF₂ to the right, causing more BaF₂ to dissolve in an attempt to restore the equilibrium concentration of F⁻ ions. 4. **Increased Solubility:** Therefore, with the decrease in F⁻ concentration due to the formation of HF, more BaF₂ will dissolve, thus increasing its solubility in the presence of a strong acid. In summary, the addition of a strong acid to a solution containing BaF₂ will increase its solubility due to the removal of F⁻ ions from the solution, shifting the equilibrium toward the dissolution of more BaF₂.
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