How will Le Chatlier’s Principle be used to? Cause an insoluble salt to become more soluble

Chemistry for Engineering Students
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Chapter12: Chemical Equilibrium
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Problem 12.52PAE: Because barium sulfate is opaque to X-rays, it is suspended in water and taken internally to make...
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How will Le Chatlier’s Principle be used to?
     Cause an insoluble salt to become more soluble

B. Solubility Equilibrium; Finding a Value for Ksp
Many ionic substances have limited water solubility. A typical example is PbCl,, which
dissolves slightly in water according to the reaction:
PBCI;(s)
Pb"aq) + 2 CI (aq)
(9)
The equilibrium constant for this reaction is:;
Kc= [Pb²*][Cl ]} = Ksp
%3D
(7)
The PbCl, does not enter into the expression because it is a solid and has no
concentration. The equilibrium constant for solubility equilibrium is called the solubility
product, Ksp.
For the above equilibrium to exist, there must be some solid PbCl, present in the system.
If there is no solid, there is no equilibrium and the Ksp is not obeyed, and [Pb][Cl ]*
must be less than the value of Ksp. If the solid is present, even in a tiny amount, then the
values of [Pb"| and [Cl ] are subject to the Ksp.
Transcribed Image Text:B. Solubility Equilibrium; Finding a Value for Ksp Many ionic substances have limited water solubility. A typical example is PbCl,, which dissolves slightly in water according to the reaction: PBCI;(s) Pb"aq) + 2 CI (aq) (9) The equilibrium constant for this reaction is:; Kc= [Pb²*][Cl ]} = Ksp %3D (7) The PbCl, does not enter into the expression because it is a solid and has no concentration. The equilibrium constant for solubility equilibrium is called the solubility product, Ksp. For the above equilibrium to exist, there must be some solid PbCl, present in the system. If there is no solid, there is no equilibrium and the Ksp is not obeyed, and [Pb][Cl ]* must be less than the value of Ksp. If the solid is present, even in a tiny amount, then the values of [Pb"| and [Cl ] are subject to the Ksp.
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