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How well did the graphical solutions agree with the measured values? 2. Why tension of the string equal to the weight on the load hanger? 3. Write the equations of equilibrium of particles

How well did the graphical solutions agree with the measured values? 2. Why tension of the string equal to the weight on the load hanger? 3. Write the equations of equilibrium of particles

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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 1. How well did the graphical solutions agree with the measured values?


2. Why tension of the string equal to the weight on the load hanger?


3. Write the equations of equilibrium of particles ?

EXPERIMENT 3 RESULTS DETERMINATION OF FORCES IN WALL JIB CRANE Table 2. Summary of experimental and theoretical results Experimental (N) -from Table 1. Theoretical (N) computed values Tension Percent Difference OBJECTIVE To determine the experimental and theoretical values of the forces in the principal parts 10.79 16.78 35,69 of the jib crane. T 32 37.17 13,9 APPARATUS REQUIRED 15981 15.981 Taring OBSERVATIONS 1. How well did the graphical solutions agree with the measured values? THEORY Free body Diagram 175.5 2. Why tension of the string equal to the weight on the load hanger? 207 3. Write the equations of equilibrium of particles. CONCLUSION
Transcribed Image Text:EXPERIMENT 3 RESULTS DETERMINATION OF FORCES IN WALL JIB CRANE Table 2. Summary of experimental and theoretical results Experimental (N) -from Table 1. Theoretical (N) computed values Tension Percent Difference OBJECTIVE To determine the experimental and theoretical values of the forces in the principal parts 10.79 16.78 35,69 of the jib crane. T 32 37.17 13,9 APPARATUS REQUIRED 15981 15.981 Taring OBSERVATIONS 1. How well did the graphical solutions agree with the measured values? THEORY Free body Diagram 175.5 2. Why tension of the string equal to the weight on the load hanger? 207 3. Write the equations of equilibrium of particles. CONCLUSION
TABULATION Determination of Experimental Values of Forces in the Principal Parts of Jib Crane: Table 1. Experimental Force results String Force Distance of Jib to Tie Force Fr Jib Force FJ Length Length (N) (N) Load W Fs=W of Tie of Jib (N) (N) (mm) (mm) Tie Load anchor Newtons pivot (mm) Kg Newtons (mm) (kgx9.81) 400 530 380 150 0 +0.981 410 610 1.2 1.7 380 150 15.981 30 15,981 15.981 (adjusted) 400 ~530 380 150 10,79 32 16,981 Find FT and Fj using the following equations: EFx=0 EFy=0 F = W E Fx = FjlcoS+1)+ FT Cos (175,5) + fs co3 (207) 4 15,981 Cos (276) =0 0,7 fj - 0,4FT - 0,8 Fg 4 0 s o fs s W s15,981w = 0,75j -0,9 fT - 0, 8 (I5,981) = o 0,7555- 0,9F- 12,7850 -o =7 5 Sin l41) 4 FTsin (175,5) + Fs Sin (2o7)415,98) Sin (27) = s 0,6 Fj +0,07FT - 72 - 5,980 6,6f5+ 0,07 FT- 23,481 =0 →の Efy 27° Sotve O 80 FJs 37)7N FS Fp s16178N * Fr a 207° Fs w3 15.98) { fy so
Transcribed Image Text:TABULATION Determination of Experimental Values of Forces in the Principal Parts of Jib Crane: Table 1. Experimental Force results String Force Distance of Jib to Tie Force Fr Jib Force FJ Length Length (N) (N) Load W Fs=W of Tie of Jib (N) (N) (mm) (mm) Tie Load anchor Newtons pivot (mm) Kg Newtons (mm) (kgx9.81) 400 530 380 150 0 +0.981 410 610 1.2 1.7 380 150 15.981 30 15,981 15.981 (adjusted) 400 ~530 380 150 10,79 32 16,981 Find FT and Fj using the following equations: EFx=0 EFy=0 F = W E Fx = FjlcoS+1)+ FT Cos (175,5) + fs co3 (207) 4 15,981 Cos (276) =0 0,7 fj - 0,4FT - 0,8 Fg 4 0 s o fs s W s15,981w = 0,75j -0,9 fT - 0, 8 (I5,981) = o 0,7555- 0,9F- 12,7850 -o =7 5 Sin l41) 4 FTsin (175,5) + Fs Sin (2o7)415,98) Sin (27) = s 0,6 Fj +0,07FT - 72 - 5,980 6,6f5+ 0,07 FT- 23,481 =0 →の Efy 27° Sotve O 80 FJs 37)7N FS Fp s16178N * Fr a 207° Fs w3 15.98) { fy so
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