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How to convert i to i^2/i and how did the negative sign appear Part B To prove sin (iz) = i sin h (z) LHS=sin (iz) = ei(iz) –e-i(iz) e-²-e? 2i 2! S= e-e 2 e-e-z e-e-z e--e? n h (z) i. 2! 2! Since, LHS-RHS. It can be proved that sin (iz) = i sin h (z)

How to convert i to i^2/i and how did the negative sign appear Part B To prove sin (iz) = i sin h (z) LHS=sin (iz) = ei(iz) –e-i(iz) e-²-e? 2i 2! S= e-e 2 e-e-z e-e-z e--e? n h (z) i. 2! 2! Since, LHS-RHS. It can be proved that sin (iz) = i sin h (z)

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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How to convert i to i^2/i and how did the negative sign appear Part B To prove sin (iz) = i sin h(z) LHS=sin (iz) eitiz) –e-i(iz) e--e 2i 2! S= n h (z) +i.-e 2 e-e-z e-e-2 e-e- e--e 2! 2! Since, LHS-RHS. It can be proved that sin (iz) = i sin h (z) ||
Transcribed Image Text:How to convert i to i^2/i and how did the negative sign appear Part B To prove sin (iz) = i sin h(z) LHS=sin (iz) eitiz) –e-i(iz) e--e 2i 2! S= n h (z) +i.-e 2 e-e-z e-e-2 e-e- e--e 2! 2! Since, LHS-RHS. It can be proved that sin (iz) = i sin h (z) ||
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